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stiv31 [10]
3 years ago
9

A force of 120 N is applied to the front of a sled so as to pull the sled a distance of 165

Physics
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

<h3>The answer is 19,800 J</h3>

Explanation:

The work done by an object can be found by using the formula

<h3>workdone = force × distance</h3>

From the question

force = 120 N

distance = 165 m

We have

work done = 120 × 165

We have the final answer as

<h3>19,800 J</h3>

Hope this helps you

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An inflatable raft (unoccupied) floats down a river at an approximately constant speed of 5.6 m/s. A child on a bridge, 71 m abo
saveliy_v [14]

Answer:

21.28 m

Explanation:

height, h = 71 m

velocity of raft, v = 5.6 m/s

let the time taken by the stone to reach to raft is t.

use second equation of motion for stone

h = ut + \frac{1}{2}at^{2}

u = 0 m/s, h = 71 m, g = 9.8 m/s^2

71 = 0 + 0.5 x 9.8 x t^2

t = 3.8 s

Horizontal distance traveled by the raft in time t

d = v x t = 5.6 x 3.8 = 21.28 m

3 0
3 years ago
A skier (m=59.0 kg) starts sliding down from the top of a ski jump with negligible friction and takes off horizontally. If h = 3
marissa [1.9K]

Answer:

35.20 m

Explanation:

By the law of conservation of energy we have,

mg(H-h)=\frac{1}{2}mv^2

g(H-h)=\frac{1}{2}v^2

\Rightarrow H=\frac{v^2}{2g}+h

where m= mass of the skier, h= 3.00 m

D= horizontal distance=13.9 m

H= maximum height attained

Also, the horizontal distance covered by the skier is

D=vt

=v\frac{2g}{h}

\Rightarrow v^2=\frac{gD^2}{2h}

thus, height H in terms of D  is given by

H=\frac{D^2}{2h}+h

H=\frac{13.9^2}{2\times3}+3

H=35.20 m

4 0
3 years ago
Please Please Please help on these 3 questions :) 20 POINTS!! - NO LINKS PLEASE
GenaCL600 [577]

Answer:

Catapult on the ground: Normal, gravity

Catapult (I'm assuming launching marshmallow): Reaction of Force Applied

Marshmallow: Force Applied

Explanation:

This is the forces that act on a stationary object and a launched object. The catapult may also experience a force friction if your teacher is taking a more practical sense.

3 0
3 years ago
An average skater averages 11 m/s over the first 5 seconds of a race. find the average speed required over next 10 seconds to av
Gelneren [198K]

Answer:

usa

Explanation:

6 0
3 years ago
Planet A has a mass of 2.25 x 1020 kg, while planet B has a
denis23 [38]

The gravitational attraction between two planets is  4905.95 N

<h3>What is gravitational attraction?</h3>

When two objects with masses are placed at a distance, there will an attractive force acting between them.

According to the Newton's law of gravitation, gravitational force is

F = Gm₁m₂ /r²

where r is the distance between the masses m₁ and m₂ and  G is the gravitational constant G = 6.67 x 10⁻¹¹ N-m²/kg²

Substitute the values into the expression, we get

F =  6.67 x 10⁻¹¹ x  2.25 x 10²⁰ x 6.20 x 10¹⁸ / (435,500 x 1000)²

F= 4905.95 N

Thus, the gravitational attraction between two planets is  4905.95 N.

Learn more about gravitational attraction.

brainly.com/question/19822389

#SPJ2

6 0
2 years ago
Read 2 more answers
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