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Vilka [71]
3 years ago
12

A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. write a quadratic function equation

that describes the height h at time t.
Physics
1 answer:
Andrei [34K]3 years ago
5 0
During upward projection the final velocity is zero, and the gravitational acceleration is -10 m/s² (against the gravity).
Therefore; using the equation;
S = 1/2gt² + ut
Where s is the height h, g is gravitational acceleration, and t is the time and u is the initial velocity u, is 16 ft/s.
Thus; h= 1/2(-10)t² + 16t
We get; h = -5t² + 16t
Therefore; the quadratic equation is 5t² - 16t + h =0
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Answer:

Frequency of the wave is 3.8 hertz.

Explanation:

It is given that, the sinusoidal wave has following wave equation as :

y(x,t)=(2.5\ m)sin[(3\ m^{-1})x-(24\ s^{-1})t+\pi/2]

The general equation for the sinusoidal wave is :

y=A\ sin(kx-\omega t+\phi)

Where

A is the amplitude

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\omega is the angular frequency

\phi is the phase difference

Since, \omega=24\ s^{-1}

2\pi f=24

f=\dfrac{24}{2\pi}=3.81\ Hz

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Paola can flex her legs from a bent position through a distance of 20.1 cm. Paola leaves the ground when her legs are straight,
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The third equation of free fall can be applied to determine the acceleration. So that Paola's acceleration during the flight is 39.80 m/s^{2}.

Acceleration is a quantity that has a direct relationship with velocity and also inversely proportional to the time taken. It is a vector quantity.

To determine Paola's acceleration, the third equation of free fall is appropriate.

i.e V^{2} = U^{2} ± 2as

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From the given question, s = 20.1 cm (0.201 m), U = 4.0 m/s, V = 0.

So that since Poala flies against gravity, then we have:

V^{2} = U^{2} - 2as

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0.402a = 16

a = \frac{16}{0.402}

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a = 39.80 m/s^{2}

Therefore Paola's acceleration is 39.80 m/s^{2}.

Visit: brainly.com/question/17493533

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2 years ago
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Answer:

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