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monitta
3 years ago
11

Hãy nêu sự tương tự giữa công của lực điện trong trường hợp này với công của trọng lực.​

Physics
1 answer:
statuscvo [17]3 years ago
6 0

Answer:

tốt ý bạn là gì?

Explanation:

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Which will increase the energy of motion of water molecules?
Allisa [31]
A) add heat will be the answer
4 0
3 years ago
What is a newton equal to in terms of mass and acceleration
Andre45 [30]
1 newton is the force that accelerates 1 kilogram of mass at the rate of 1 meter per second^2. / / / 1N = 1 kg-m / sec^2 .
8 0
3 years ago
Which of the following represent units of an electric field? select all that apply
zimovet [89]

Answer:

Volts/Meter

Newtons/Coulomb

Explanation:

Volts/ Meter and Newtons/Coulomb both are same and the units of Electric field intensity or electric field strength.

Electric field strength E is the force per unit charge. It is measured in Newton/Coulomb in SI unit. It is a vector quantity directed in the direction of force.

Mathematically,

           Electric field strength = Force/Charge

                                           E = F / q₀

                                               = Newton / Coulomb = NC⁻¹             1

We know that

                         Newton = Joule/meter            2

Also

                           Volt = Joule/Coulomb             3

So put 3 in 2 we get

                          Newton = (Volt Coulomb)/meter       put in 1

   

                            E =  (Volt Coulomb)/(meter Coulomb)

                               = Volt / meter

Hence

                  Newton / Coulomb = Volt / meter    

                         

                                               

8 0
3 years ago
Read 2 more answers
A golden-colored cube is handed to you. The person wants you to buy it for $100, saying that is a gold nugget. You pull out your
kenny6666 [7]

Answer:

Explanation:

Volume of cube=side³

=2*2*2

=8 cm³

Mass of cube=40g

Its density=mass/volume

=5g/cm³

which differs the value given in the text hence it is not gold and u should not bye it...

Instead u should call the police for arresting the person lol...

6 0
3 years ago
Read 2 more answers
The astronomical unit (AU) is defined as the mean center-to-center distance from Earth to the Sun, namely 1.496x10^(11) m. The p
Rudiy27

Answer:

a) How many parsecs are there in one astronomical unit?

4.85x10^{-6}pc

(b) How many meters are in a parsec?

3.081x10^{16}m

(c) How many meters in a light-year?

9.46x10^{15}m

(d) How many astronomical units in a light-year?

63325AU

(e) How many light-years in a parsec?

3.26ly

Explanation:

The parallax angle can be used to find out the distance using triangulation. Making a triangle between the nearby star, the Sun and the Earth, knowing that the distance between the Earth and the Sun (1.496x10^{11} m) is defined as 1 astronomical unit:

\tan{p} = \frac{1AU}{d}

Where d is the distance to the star.

Since p is small it can be represent as:

p(rad) = \frac{1AU}{d}  (1)

Where p(rad) is the value of in radians

However, it is better to express small angles in arcseconds

p('') = p(rad)\frac{180^\circ}{\pi rad}.\frac{60'}{1^\circ}.\frac{60''}{1'}

p('') = 2.06x10^5 p(rad)

p(rad) = \frac{p('')}{2.06x10^5} (2)

Then, equation 2 can be replace in equation 1:

\frac{p('')}{2.06x10^5} = \frac{1AU}{d}  

\frac{d}{1AU} = \frac{2.06x10^5}{p('')}  (3)

From equation 3 it can be see that 1pc = 2.06x10^5 AU

<em>a) How many parsecs are there in one astronomical unit? </em>

1AU . \frac{1pc}{2.06x10^5AU} ⇒ 4.85x10^{-6}pc

<em>(b) How many meters are in a parsec? </em>

2.06x10^{5}AU . \frac{1.496x10^{11}m}{1AU} ⇒ 3.081x10^{16}m

<em>(c) How many meters in a light-year? </em>

To determine the number of meters in a light-year it is necessary to use the next equation:

x = c.t

Where c is the speed of light (c = 3x10^{8}m/s) and x is the distance that light travels in 1 year.

In 1 year they are 31536000 seconds

x = (3x10^{8}m/s)(31536000s)

x = 9.46x10^{15}m

<em>(d) How many astronomical units in a light-year?</em>

9.46x10^{15}m . \frac{1AU}{1.496x10^{11}m} ⇒ 63325AU

<em>(e) How many light-years in a parsec?</em>

2.06x10^{5}AU . \frac{1ly}{63235AU} ⇒ 3.26ly

5 0
3 years ago
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