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Elenna [48]
2 years ago
13

Consider two different solutions of the same UV-absorbing compound. Upon UV-analysis, Solution B gave an absorbance of 1.0 and S

olution A gave an absorbance of 0. 4 at the same wavelength. Solution B is higher in concentration than Solution A by what ratio (or percentage)
Chemistry
1 answer:
Juliette [100K]2 years ago
7 0

We have that the Concentration of solution B is 2.5 times more than solution A's concentration.

<h3>UV(Ultra violent) rays</h3>

Question Parameters:

Upon UV-analysis, Solution B gave an absorbance of 1.0

Solution A gave an absorbance of 0. 4

Generally the equation for the Absorbance    is mathematically given as

A = e*c*L

Therefore

For A solution  

0.4 = e*[cA]*L

For B solution  

1.0 = e*[cB]*L

Hence

\frac{0.4}{ 1} = \frac{[cA]}{ cB}

[cB] = 2.5 [cA]

Therefore

Concentration of solution B is 2.5 times more than solution A's concentration.

For more information on Wave visit

brainly.com/question/3004869

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During combustion, methane yields carbon dioxide and water. The unbalanced equation for this reaction is:CH4(g)+O2(g) → CO2(g)+
almond37 [142]

Answer:

CH₄(g)  +  2O₂(g) → CO₂(g)  +  2H₂O(l)

Mole ratios for the balanced equation be:

1:2, 2:1, 1:1, 1:2, 2:2

Explanation:

CH4(g)+O2(g) → CO2(g)+ H2O(l)

To balance a chemical equation, you must have the same mole of each element in both sides of the reaction (reactant side and product side)

CH₄(g)  +  2O₂(g) → CO₂(g)  +  2H₂O(l)

2 C

8 H

8 O

In  both side.

It takes 1 mole of methane to react with 2 mole of oxygen in order to produce 1 mol of dioxide and 2 mole of water.

Mole ratios for the balanced equation be:

Mole ratios for the balanced equation be:

1:2, 2:1, 1:1, 1:2, 2:2  - We should compare each compound

1 mol methane → 2 mole of oxygen

2 mole of oxygen → 1 mol of methane

2 mole of oxygen → 1 mol of dioxide

1 mole of dioxide → 1 mol of Methane

2 mole of water → 2 mole of oxygen (the same as opposite)

1 mol methane →  2 mole of water

2 mol of water → 1 mol of methane

4 0
3 years ago
When 125 grams of FeO react with 25.0 grams of Al, how many grams of Fe can be produced? FeO + Al → Fe + Al2O3 25.9 g Fe 38.7 g
Serga [27]

<u>Answer:</u> The mass of iron produced will be 77.6 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

  • <u>For FeO:</u>

Given mass of FeO = 125 g

Molar mass of FeO = 71.8 g/mol

Putting values in equation 1, we get:

\text{Moles of FeO}=\frac{125g}{71.8g/mol}=1.74mol

  • <u>For aluminium:</u>

Given mass of aluminium = 25.0 g

Molar mass of aluminium = 27 g/mol

Putting values in equation 1, we get:

\text{Moles of aluminium}=\frac{25.0g}{27g/mol}=0.93mol

The given chemical reaction follows:

3FeO+2Al\rightarrow 3Fe+Al_2O_3

By Stoichiometry of the reaction:

2 moles of aluminium metal reacts with 3 mole of FeO

So, 0.93 moles of aluminium metal will react with = \frac{3}{2}\times 0.93=1.395mol of FeO

As, given amount of FeO is more than the required amount. So, it is considered as an excess reagent.

Thus, aluminium metal is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of aluminium metal produces 3 mole of iron metal

So, 0.93 moles of aluminium metal will produce = \frac{3}{2}\times 0.93=1.395moles of iron metal

  • Now, calculating the mass of iron metal from equation 1, we get:

Molar mass of iron = 55.85 g/mol

Moles of iron = 1.395 moles

Putting values in equation 1, we get:

1.395mol=\frac{\text{Mass of iron}}{55.85g/mol}\\\\\text{Mass of iron}=(1.395mol\times 55.85g/mol)=77.6g

Hence, the mass of iron produced will be 77.6 grams

4 0
3 years ago
What are the roles of the mucous select two options PLEASE HELP​
Oliga [24]

Answer:

The answer is A and C

8 0
3 years ago
Is C2S6 ionic or covalent
Stels [109]

Answer:

covalent

Explanation:

C2S6 is a compound made of 2 nonmetals which makes it covalent

Hope this helps! Plz mark brainliest

8 0
3 years ago
What would the products of a double-replacement reaction between KBr and CaO be? (Remember: In double-replacement reactions, the
11111nata11111 [884]

ANSWER

\begin{gathered} \text{ 2KBr }+\text{ CaO }\rightarrow\text{ K}_2O\text{ }+\text{ CaBr}_2 \\ Option\text{ B} \end{gathered}

EXPLANATION

Given that;

The two reactants are KBr and CaO

Double replacement reaction is a type of chemical reaction that occur when two reactants exchange cations and anions to yield new products.

\text{ 2KBr + CaO  }\rightarrow\text{ K}_2O\text{ + CaBr}_2

Therefore, the resulting products of the given data are K2O + CaBr2

The correct answer is option B

4 0
1 year ago
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