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Elenna [48]
2 years ago
13

Consider two different solutions of the same UV-absorbing compound. Upon UV-analysis, Solution B gave an absorbance of 1.0 and S

olution A gave an absorbance of 0. 4 at the same wavelength. Solution B is higher in concentration than Solution A by what ratio (or percentage)
Chemistry
1 answer:
Juliette [100K]2 years ago
7 0

We have that the Concentration of solution B is 2.5 times more than solution A's concentration.

<h3>UV(Ultra violent) rays</h3>

Question Parameters:

Upon UV-analysis, Solution B gave an absorbance of 1.0

Solution A gave an absorbance of 0. 4

Generally the equation for the Absorbance    is mathematically given as

A = e*c*L

Therefore

For A solution  

0.4 = e*[cA]*L

For B solution  

1.0 = e*[cB]*L

Hence

\frac{0.4}{ 1} = \frac{[cA]}{ cB}

[cB] = 2.5 [cA]

Therefore

Concentration of solution B is 2.5 times more than solution A's concentration.

For more information on Wave visit

brainly.com/question/3004869

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This is an incomplete question, here is a complete question.

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Perform the following calculations:

A) Calculate ΔS at 298 K (ΔH= -220 kJ/mol and ΔG= -206 kJ/mol

B) Assuming that ΔS and ΔH change little with temperature, calculate ΔG at 450 K.

Answer :

(a) The value of ΔS at 298 K is, -0.0469 kJ/mol.K

(b) The value of ΔG at 450 K is, -199 kJ/mol

Explanation :

(a) According to Gibb's equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibbs free energy = -206 kJ/mol

\Delta H = enthalpy change  = -220 kJ/mol

\Delta S = entropy change = ?

T = temperature in Kelvin = 298 K

Now put all the given values in the above formula, we get:

-206kJ/mol=-220kJ/mol-298K\times \Delta S

\Delta S=-0.0469kJ/mol.K

Thus, the value of ΔS at 298 K is, -0.0469 kJ/mol.K

(b) According to Gibb's equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibbs free energy = ?

\Delta H = enthalpy change  = -220 kJ/mol

\Delta S = entropy change = -0.0469 kJ/mol.K

T = temperature in Kelvin = 450 K

Now put all the given values in the above formula, we get:

\Delta G=-220kJ/mol-450K\times -0.0469 kJ/mol.K

\Delta G=-198.895kJ/mol\approx -199kJ/mol

Thus, the value of ΔG at 450 K is, -199 kJ/mol

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