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Novay_Z [31]
3 years ago
15

What statements is equal to the expression p\11

Mathematics
1 answer:
V125BC [204]3 years ago
5 0

Answer: "p divided by 11" or "p over 11" or "p by 11".

Step-by-step explanation:

We use mathematical statements to express any algebraic expression.

For example: We write 2x as "2 is multiplied by x " or " product of 2 and x".

p+q as "sum of p and q" or "p is added to q"

The given expression is : \dfrac{p}{11}

In mathematical statements, it can be written as "p divided by 11" or "p over 11" or "p by 11".

Hence, the statements are equal to the expression  \dfrac{p}{11} are "p divided by 11" or "p over 11" or "p by 11".

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Suppose a city with population 300 comma 000 has been growing at a rate of 3​% per year. If this rate​ continues, find the popul
viktelen [127]

Answer:

The population of this city in 13 years is 440,550.

Step-by-step explanation:

Given:

Suppose a city with population 300, 000 has been growing at a rate of 3​% per year.

Now, to find the population of this city in 13 years.

Let the population of this city in 13 years be A.

Population (P) = 300,000.

Rate per year (r) = 3%.

Time (t) = 13 years.

Now, we put formula to get the population of the city in 13 years:

A=P(1+r)^t\\\\A=300,000(1+3\%)^{13}\\\\A=300,000(1+0.03)^{13}\\\\A=300,000(1.03)^{13}\\\\A=300,000\times 1.4685\\\\A=440,550.

Therefore, the population of this city in 13 years is 440,550.

3 0
3 years ago
(a) Let R = {(a,b): a² + 3b <= 12, a, b € z+} be a relation defined on z+)
grin007 [14]

Answer:

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Step-by-step explanation:

The relation R is an equivalence if it is reflexive, symmetric and transitive.

The order to options required to show that R is an equivalence relation are;

((a, b), (a, b)) ∈ R since a·b = b·a

Therefore, R is reflexive

If ((a, b), (c, d)) ∈ R then a·d = b·c, which gives c·b = d·a, then ((c, d), (a, b)) ∈ R

Therefore, R is symmetric

If ((c, d), (e, f)) ∈ R, and ((a, b), (c, d)) ∈ R therefore, c·f = d·e, and a·d = b·c

Multiplying gives, a·f·c·d = b·e·c·d, which gives, a·f = b·e, then ((a, b), (e, f)) ∈R

Therefore R is transitive

From the above proofs, the relation R is reflexive, symmetric, and transitive, therefore, R is an equivalent relation.

Reasons:

Prove that the relation R is reflexive

Reflexive property is a property is the property that a number has a value that it posses (it is equal to itself)

The given relation is ((a, b), (c, d)) ∈ R if and only if a·d = b·c

By multiplication property of equality; a·b = b·a

Therefore;

((a, b), (a, b)) ∈ R

The relation, R, is reflexive.

Prove that the relation, R, is symmetric

Given that if ((a, b), (c, d)) ∈ R then we have, a·d = b·c

Therefore, c·b = d·a implies ((c, d), (a, b)) ∈ R

((a, b), (c, d)) and ((c, d), (a, b)) are symmetric.

Therefore, the relation, R, is symmetric.

Prove that R is transitive

Symbolically, transitive property is as follows; If x = y, and y = z, then x = z

From the given relation, ((a, b), (c, d)) ∈ R, then a·d = b·c

Therefore, ((c, d), (e, f)) ∈ R, then c·f = d·e

By multiplication, a·d × c·f = b·c × d·e

a·d·c·f = b·c·d·e

Therefore;

a·f·c·d = b·e·c·d

a·f = b·e

Which gives;

((a, b), (e, f)) ∈ R, therefore, the relation, R, is transitive.

Therefore;

R is an equivalence relation, since R is reflexive, symmetric, and transitive.

Based on a similar question posted online, it is required to rank the given options in the order to show that R is an equivalence relation.

Learn more about equivalent relations here:

brainly.com/question/1503196

4 0
2 years ago
Pls help me on question 2
boyakko [2]

Answer:

For this one, your answer will be

(x-8) would describe the case here planes grew 8 inches but x inches this weak.

Step-by-step explanation:

hope it helps

have a great day!!

8 0
2 years ago
Read 2 more answers
Lester bought 6.73 pounds of bologna at the deli. Renee bought 1.41 pounds of bologna. How much more bologna did Lester buy than
atroni [7]

Answer:

5.32

Step-by-step explanation:

You would have to subtract 6.73-1.41.

5 0
3 years ago
What is the solution for 5(m-3) ≥ 7m-2.4 ?
shtirl [24]

Answer:

Step-by-step explanation:

5(m-3)≥7m-2.4

5m-15≥7m-2.4

2m≤-12.6

m≤-6.1

7 0
3 years ago
Read 2 more answers
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