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Aleks [24]
3 years ago
7

an object of mass 1kg was at rest before it fell through a height o 5m and hit the ground. Calculate the initial gravitational p

otential energy of the object
Physics
2 answers:
chubhunter [2.5K]3 years ago
7 0
\bold{Hello  \:\:  Friend}


Given :-

=> mass = 1 kg
=> height = 5 m


Potential energy = m*g*h

→ 1*10*5



Potential energy = 50 J




Hope It helps you. ^_^
viva [34]3 years ago
3 0

Hello!

Data:

h = 5 m

m = 1 Kg

PE = ? (Joule)

Adopting, gravity (g) ≈ 10 m/s²

Formula:

PE_{grav}  = mass * g * height

Solving:

PE_{grav} = mass * g * height

PE_{grav} = 1*10*5

\boxed{\boxed{PE_{grav} = 50\:J}}\end{array}}\qquad\checkmark

I Hope this helps, greetings ... DexteR! =)

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A battery is used to charge a parallel-plate capacitor, after which it is disconnected. Then the plates are pulled apart to twic
Igoryamba

Answer: C.

Explanation:

For a parallel-plate capacitor where the distance between the plates is d.

The capacitance is:

C = e*A/d

You can see that the distance is in the denominator, then if we double the distance, the capacitance halves.

Now, the stored energy can be written as:

E = (1/2)*Q^2/C

Now you can see that in this case, the capacitance is in the denominator, then we can rewrite this as:

E = (1/2)*Q^2*d/(e*A)

e is a constant, A is the area of the plates, that is also constant, and Q is the charge, that can not change because the capacitor is disconnected.

Then we can define:

K = (1/2)*Q^2/(e*A)

And now we can write the energy as:

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Then the energy is proportional to the distance between the plates, this means that if we double the distance, we also double the energy.

8 0
3 years ago
A light has wavelength of is used in the double slits experiment . Which of the following values represent the phase difference
Wewaii [24]

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s

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A block of mass m is pushed a horizontal distance D from position A to position B, along a horizontal plane with friction coeffi
Wewaii [24]

Answer:

The total work done by friction is -2 · μ · m · g · D

Explanation:

Hi there!

The work done by a force is calculated as follows:

W = F · d · cos θ

Where:

W = work.

F = force that does the work.

d = displacement.

θ = angle between the displacement and the force.

If the force is horizontal, as in this case, cos θ = 1

The friction force is calculated as follows:

Ffr = μ · m · g

Where:

μ = friction coefficient.

m = mass of the object.

g = acceleration due to gravity.

Then, in this case, the work done by friction when pushing the block from A to B will be:

W AB = -Ffr · D

W AB = - μ · m · g · D

Notice that the friction force is negative because it is opposite to the pushing force P.

When the block is pushed from B to A, the work done by friction will be:

W BA = Ffr · (-D)

W BA = -μ · m · g · D

Now, the displacement is negative and the friction force is positive (in the opposite direction to -P).

The total work done by friction will be:

W AB + W BA = - μ · m · g · D  - μ · m · g · D  = -2 μ · m · g · D

5 0
3 years ago
At a certain location, Earth has a magnetic field of 0.60 ✕ 10−4 T, pointing 75° below the horizontal in a north-south plane. A
saveliy_v [14]

Answer with Explanation:

We are given that

Magnetic field,B=0.6\times 10^{-4} T

\theta=75^{\circ}

Length of wire,l=15 m

Current,I=19 A

a.We have to find the magnitude of magnetic force and direction of magnetic force.

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Using the formula

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F=16.5\times 10^{-3} N

Direction=tan\theta=cot(90-75)=tan15^{\circ}

\theta=15^{\circ}

15 degree above the horizontal  in the northward direction.

5 0
3 years ago
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