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3 years ago

How long does it take for 4 coulombs of charge to pass through a cross

Physics

1 answer:

Galina-37 [17]3 years ago

4 0

Answer: 2 seconds

Explanation:

Given that,

Time (T) = ?

Charge (Q) = 4 coulombs

current (I) = 2 Amps

Since charge depends on the amount of current flowing through the wire in a given time, hence

Charge = Current x Time

Q = IT

4 coulombs = 2 Amps x Time

Time = 4 coulombs / 2 Amps

Time = 2 seconds

Thus, it takes 2 seconds for the current to flow through the wire

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Answer:

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3 years ago

A 720 kg roller-coaster starts off from Location A. Assuming friction does not impede the car's motion, what will be the change

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3 years ago

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A hair dryer is basically a duct of constant diameter in which a few layers of electric resistors are placed. A small fan pulls

Mars2501 [29]

Answer:

Therefore % increase in velocity is 18.23 %

Explanation:

we use the equality of mass flow rate and the areas

$m_1 = m_2\\p_1v_1 = p_2v_2\\p_1A_1v_1 = p_2A_2v_2\\v_2 = \frac{p_1}{p_2} v_1$

The percentage increase in velocity is

Δ v% = $\frac{v_2 - v_1}{v_1} \\$ 100%

= $\frac{p_1}{p_2} v_1 - v_1$ .100%

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3 years ago

A hammer slides down a roof that makes a 30.0°angle with the horizontal. What are the magnitudes of the components of the hammer

dlinn [17]

<h2>Answer:7.14 $ms^{-1}$ ,4.125 $ms^{-1}$ </h2>

Explanation:

Whenever an object is moving in a 2D frame,its motion can be analysed as if it is travelling in two independent 1D frames.

One of such independent 1D frames are along horizontal and another along vertical.

Let $v$ be the total velocity.

Given that, $v=8.25ms^{-1}$

We call the horizontal velocity as $v_{h}$ and the vertical velocity as $v_{v}$ .

$v_{h}$ = $vCos\alpha$

$v_{v}=vSin\alpha$

where $\alpha$ is the angle between the object and horizontal.

It is given that $\alpha =30^{0}$

$v_{h}=8.25\times Cos(30^{0})=7.14ms^{-1}$

$v_{v}=8.25\times Sin(30^{0})=4.125ms^{-1}$

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3 years ago

What vibrates in an EM wave

AlladinOne [14]

Answer:magnetic and electric fields

Explanation:

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