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2 years ago

Show your working please

Physics

1 answer:

saw5 [17]2 years ago

3 0

Explanation:

There's not enough information in the problem to solve it. We need to know either the initial speed of the lorry, or the time it takes to stop.

For example, if we assume the initial speed of the lorry is 25 m/s, then we can find the rate of deceleration:

v² = v₀² + 2aΔx

(0 m/s)² = (25 m/s)² + 2a (50 m)

a = -6.25 m/s²

We can then use Newton's second law to find the force:

F = ma

F = (7520 kg) (-6.25 m/s²)

F = -47000 N

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2 years ago

John’s mass is 95.6 kg, and Barbara’s is 55.3 kg. He is standing on the x axis at xJ = +10.9 m, while she is standing on the x a

Anna11 [10]

Answer:Shifted towards Left by distance of 2.243 m

Explanation:

Given

Mass of john $m_1=95.6 kg$

Mass of barbara $m_2=55.3 kg$

John is standing at $x=10.9 m$

Barbara is standing at $x=2.50 m$

$x_{com}=\frac{m_1x_1+m_2x_2}{m_1+m_2}$

$x_{com}=\frac{95.6\times 10.9+55.3\times 2.5}{95.6+55.3}$

$x_{com}=\frac{1180.29}{150.9}$

$x_{com}=7.821 m$

Now if they change their Position then

$x'_{com}=\frac{95.6\times 2.5+55.3\times 10.9}{95.6+55.3}$

$x'_{com}=\frac{841.77}{150.9}$

$x'_{com}=5.578$

Thus we can see that center of mass shifted towards left by a distance of $2.243 m$ because heavier is shifted towards left

8 0

2 years ago

Show your working please ​

Show your working please