For energy released from vaporisation,
Q(Energy) = m(mass of vapour) X l (latent heat of vaporisation)
= (0.65) X (2257)
Formula for calculating [Average Atomic Mass] of Pb (Lead):AAM of [element] = (Mass of isotope) * (Relative abundance) and you can repeat the "(Mass of isotope) * (Relative abundance)" part for each isotope! Therefore...AAM of Pb=(203.97302)(0.014)+(205.97444)(0.241)+(206.97587)(0.221)+(207.97663)(0.524)AAM of Pb = 207.21688371 amu [OR] 207.2 amu on most periodic tables.
Answer:
Verb. Load with too great a burden or cargo.
"Both boats were overloaded and low in the water"
Noun. An excessive load or amount.
"an overload of stress"
Explanation:
Similar words are strain, excess, and overburden.
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The tension in the rod when the ratio of speed is 8 is 1.34 × 10⁴ N.
The longitudinal waves speed is determined using the density of the material and the Youngs modulus with the expression:
v = √(Y/rho)
A wave in a stretched string can be used to represent the transverse wave.
The length of the metal rod is 150 cm and the radius of the rod is cm.
The mass of the rod is 50.9 g.
Now, the Youngs modulus for the material is 6.80× 10¹⁰ N/m².
For the longitudinal wave
v(l) = (Y/ρ)^{1/2}
For the transverse wave :
v(T) = (Y/μ)^{3/2}
Now, we need
v(L) / v(T) = 8
And we know,
T = (μY) / (64ρ) where μ= m /L
And the density, ρ = mass / volume = (m) / (πr²L)
Therefore,
T = (πr²Y) / 64
T = (π)(2 × 10⁻³)² × (6.8 × 10¹⁰) / 64
T = 1.34 × 10⁴ N
Learn more about longitudinal waves here:
brainly.com/question/25827374
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