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Brums [2.3K]
2 years ago
12

Which of the following statements is true?

Physics
2 answers:
makvit [3.9K]2 years ago
5 0

Answer:

I think c

Explanation:

hope that helps

Alex_Xolod [135]2 years ago
5 0
Definitely is C hopefully it is C
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¿Cómo es el movimiento uniforme de los pedales de una bicicleta con respeto a la tierra y con respecto al ciclista?
Nastasia [14]
Respecto al ciclista
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3 years ago
A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po
Umnica [9.8K]

Answer:

V1 =8.1 m/s

Explanation:

height at highest point (h2) = 4.1 m

height at lowest point (h1) = 0.8 m

acceleration due to gravity (g) = 9.8 m/s^{2}

from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + 0.5mV1^{2} = mgh2 + 0.5mV2^{2}

where

  • speed at highest point = V2
  • speed at lowest point = V1
  • mass of the girl and swing = m
  • at the highest point, the  speed is minimum (V1 = 0)
  • at the lowest point the speed is maximum (V2 is the maximum speed)
  • therefore the equation becomes mgh1 + 0.5mV1^{2} = mgh2

      m(gh1 + 0.5V1^{2}) = m(gh2)

      gh1 + 0.5V1^{2} = gh2

      V1 = \sqrt{\frac{gh2 - gh1}{0.5}}

now we can substitute all required values into the equation above.

V1 = \sqrt{\frac{(9.8x4.1) - (9.8x0.8)}{0.5}}

V1 = \sqrt{\frac{32.34}{0.5}}

V1 =8.1 m/s

8 0
4 years ago
What are the methods of storing tools
irina [24]
You might want to visit this website
https://www.nedcc.org/free-resources/preservation-leaflets/4.-storage-and-handling/4.1-storage-metho...
8 0
3 years ago
What is the maximum number of lines per centimeter a diffraction grating can have and produce a complete first-order spectrum fo
Pachacha [2.7K]

Answer:

14,300 lines per cm

Explanation:

Answer:

14,300 cm per line

Explanation:

λ400 nm to 400nm

We can find the maximum number of lines per centimeter, which is reciprocal of the least distance separating two adjacent slits, using the following equation.

mλ = dsin (θ)

In this equation,

m is the order of diffraction.

λ is the wavelength of the incident light.

d is the distance separating the centers of the two slits.

θ is the angle at which the mth order would diffract.

To find the least separation that allows the observation of one complete order of spectrum of the visible region, we use the maximum wavelength of the visible region is 700 nm.

d =  mλ / sin (θ)

As we want the distance d to be the smallest then sin (θ) must be the greatest, and the greatest value of the sin (θ) is 1. For that we also use the longest wavelength because using the smallest wavelength, the longest wavelength would not be diffracted.

d =  mλ / sin (θ)

d =  1 x 700nm / 1

  = 700 nm

So, the least separation that would allow for the possibility of observing complete first order of the visible region spectra is 700 nm, and knowing the least separation we can find the maximum number of lines per cm, which is the reciprocal of the number of lines per cm.

n = 1/d

   = 1 / 700 x 10^{-9}

  = 1, 430,000 lines per m  

  =  14,300 lines per cm

<u>The maximum number of lines per cm, that would allow for the observation of the complete first order visible spectra.</u>

5 0
3 years ago
If the atomic radius of Copper is 0.128 nm, calculate the volume of its unit cell in cubic nanometers. Round off the answer to t
hodyreva [135]

Explanation:

Below is an attachment containing the solution.

4 0
4 years ago
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