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Nikitich [7]
3 years ago
15

Iron (III) oxide pentahydrate formula

Chemistry
1 answer:
Nina [5.8K]3 years ago
4 0

Answer:

Molecular Formula Fe2O12S3·5H2O

IUPAC Name iron(3+);tri sulfate;pentahydrate

Explanation:

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I think your question is incorrect

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Help meeee!<br> 3874 dkg = _____ dg
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A student lives in a place that receives lots of snow and ice during the winter. The student has observed that the highway depar
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Combustion analysis of a 13.42-g sample of the unknown organic compound (which contains only carbon, hydrogen, and oxygen) produ
pentagon [3]

Answer: molecular formula = C12H16O8

Explanation:

NB Mm CO2= 44g/mol

Mm H2O= 18g/mol

Moles of CO2 = 36.86/44=0.84mol

0.84mole of CO2 has 0.84 mol of C

Moles of H2O = 10.06/18= 0.56mol

1mol of H20 contains 1mol of O and 2 mol H,

Hence there are 0.56mol O and (0.56×2)mol H

Hence the compound contains

C= 0.84 mol H= 1.12mol O=0.56mol

Divide through by smallest number

C= 0.83/0.56= 1.5mol

H= 1.12/0.55= 2mol

O= 0.56/0.56= 1mol

Multiply all by 2 to have whole number of moles = 3:4:2

Hence empirical formula= C3H4O2

(C3H4O2)n = 288.38

[(12×3) + 4+(16×2)]n= 288.38

72n=288.38

n= 4

:. Molecular formula=(C3H4O2)4= C12H16O8

7 0
3 years ago
How many molecules are there in 42 grams of AIF3
Sever21 [200]

Answer:

The correct answer is - 3.012×10^23  molecules

Explanation:

The number of molecules is present in any mole of an element or compound are the same. To find the molecules you need to multiply the number of the moles of the compound by Avogadro's number:

Moles are calculated from the molecular weight, for AlF3

= 26.98 + 3×19

= 26.98 + 57

= 83.98

Then moles in 42 grams:

= 42/83.98

= 0.5001190 moles

Now the number of molecules = moles*Avogadro's number

= 0.500110×6.022×10^23

= 3.011×10^23  molecules

7 0
3 years ago
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