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Karolina [17]
3 years ago
7

Food web diagrams the interactions between organisms based on which organisms others are eating. A scientist is using a food web

to predict the predator-prey relationship of a population. What can a food web best be classified as?
A. a mean
B. a graph
C. a model
D. a range
Chemistry
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

model

Explanation:

edge 2020

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If 20.0 g of NaOH is added to 0.750 L of 1.00 M Cd(NO₃)₂, how many grams of Cd(OH)₂ will be formed in the following precipitatio
bulgar [2K]

Answer:

m_{Cd(OH)_2}=36.6 gCd(OH)_2

Explanation:

Hello.

In this case, for the given chemical reaction, in order to compute the grams of cadmium hydroxide that would be yielded, we must first identify the limiting reactant by computing the yielded moles of that same product, by 20.0 grams of NaOH (molar mass = 40 g/mol) and by 0.750 L of the 1.00-M solution of cadmium nitrate as shown below considering the 1:2:1 mole ratios respectively:

n_{Cd(OH)_2}^{by\ NaOH}=20.0gNaOH*\frac{1molNaOH}{40gNaOH} *\frac{1molCd(OH)_2}{2molNaOH} =0.25molCd(OH)_2\\\\n_{Cd(OH)_2}^{by\ Cd(NO_3)_2}=0.750L*1.00\frac{molCd(NO_3)_2}{L}*\frac{1molCd(OH)_2}{1molCd(NO_3)_2}  =0.75molCd(OH)_2

Thus, since 20.0 grams of NaOH yielded less of moles of cadmium hydroxide, NaOH is the limiting reactant, therefore the mass of cadmium hydroxide (molar mass = 146.4 g/mol) is:

m_{Cd(OH)_2}=0.25molCd(OH)_2*\frac{146.4gCd(OH)_2}{1molCd(OH)_2} \\\\m_{Cd(OH)_2}=36.6 gCd(OH)_2

Best regards.

4 0
3 years ago
What does saturated mean in science?<br>​
Sergeu [11.5K]

A saturated is one in which the atoms are linked by single bonds. :)

5 0
3 years ago
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Why is the solar system often referred to as the sun’s family ?
snow_tiger [21]

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Explanation:

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Formulate a hypothesis based on something recently observed.
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3 0
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Suppose 0.274 mol of a gas occupy 6.62 l at a given temperature and pressure. what volume will 0.878 mol occupy at the same temp
Taya2010 [7]
The  volume  that    0.878  mol  occupy  at   the  same   temperature  and  pressure   is  calculated  as follows


if   0.274  mol  occupy  6.62 L  what  about  0.878  mol

by   cross   multiplication

=0.878 x6.62/0.274=21.21 L
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