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Paha777 [63]
3 years ago
5

Scientists use specific processes to evaluate information in order to determine its accuracy and reliability. A scientist is con

ducting research to determine the growth of tagged fish in a specific lake. What process would the scientist use in order to evaluate both the new information they have gained and the information they already know about the tagged fish at the same time?
Physics
2 answers:
solmaris [256]3 years ago
7 0
The answer would be hypothesis testing
Marina CMI [18]3 years ago
6 0
The correct answer would be 
Hypothesis Testing.
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PLEASE HELP WILL MARK BRAINLIEST
loris [4]

Answer:

Protium

Explanation: Protium is an isotope of hydrogen that is composed of one proton and one electron. It is the most abundant form of hydrogen.

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A car starts at the top of a hill with 200 J of energy, and rolls down a frictionless surface. The isolated system consists of t
Kamila [148]

Answer:

The total energy stays the same but is converted from being stored as gravitational potential energy into kinetic energy of the car as it moves.

Explanation:

the law of conservation of energy states that the total energy of an isolated system remains constant, and since it is gaining speed that energy will be kinetic

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3. What is the acceleration of a 10 kg mass pushed by a 5 N force?
insens350 [35]

Answer:

F=ma

Plug it in:

5=10a

5/10=(10a)/10

.5m/s²=a

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Brainliest?

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Calculate the self-inductance (in mH) of a 45.0 cm long, 10.0 cm diameter solenoid having 1000 loops. mH (b) How much energy (in
Karo-lina-s [1.5K]

Answer:

(a) The self inductance, L = 21.95 mH

(b) The energy stored, E = 4.84 J

(c) the time, t = 0.154 s

Explanation:

(a) Self inductance is calculated as;

L = \frac{N^2 \mu_0 A}{l}

where;

N is the number of turns = 1000 loops

μ is the permeability of free space = 4π x 10⁻⁷ H/m

l is the length of the inductor, = 45 cm = 0.45 m

A is the area of the inductor (given diameter = 10 cm = 0.1 m)

A = \pi r^2 = \frac{\pi d^2}{4} = \frac{\pi \times (0.1)^2}{4} = 0.00786 \ m^2

L = \frac{(1000)^2 \times (4\pi \times 10^{-7}) \times (0.00786)}{0.45} \\\\L = 0.02195 \ H\\\\L = 21.95 \ mH

(b) The energy stored in the inductor when 21 A current ;

E = \frac{1}{2}LI^2\\\\E = \frac{1}{2} \times (0.02195) \times (21) ^2\\\\E = 4.84 \ J

(c) time it can be turned off if the induced emf cannot exceed 3.0 V;

emf = L \frac{\Delta I}{\Delta t} \\\\t = \frac{LI}{emf} \\\\t = \frac{0.02195 \times 21}{3} \\\\t = 0.154 \ s

3 0
3 years ago
Two arrows are shot vertically upward. the second arrow is shot after the first one, but while the first is still on its way up.
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<span>Now that you know the time to reach its maximum height, you have enough information to find out the initial velocity of the second arrow. Here's what you know about it: its final velocity is 0 m/s (at the maximum height), its time to reach that is 2.8 seconds, but wait! it was fired 1.05 seconds later, so take off 1.05 seconds so that its time is 1.75 seconds, and of course gravity is still the same at -9.8 m/s^2. Plug those numbers into the kinematic equation (Vf=Vi+a*t, remember?) for 0=Vi+-9.8*1.75 and solve for Vi to get....... 17.15 m/s</span>
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