Many of the boating fatalities take place after capsize, but a modest list of things to do before and after a capsize can minimize boat accidents and boat accident injuries.
Initially there is an significant list of thing to do before you even step on the boat:
1. Take the boat safety and water safely courses
2. Make certain that yourself and everyone else on the boat is wearing a well-fitting and safe life jacket.
3. Go over the place of the safety items with everyone on the boat as well as the location of the horn of the boat and the flare of the boat.
4. Paint bright color the hull of the boat in order to be seen easily from the air.
After a capsize, there are significant steps to make
1. Stay calm
2. Execute a head count and check everybody for injuries or immediate dangers.
3. Ensure that everyone has floatation device that coolers and other items that can be used.
4. Stay in the capsized boat unless dangerous.
5. Try to right the boat if someone has a knowledge on how to do so.
6. Use signal devices such as flares, bright colored life jacket, whistles, flashlights and mirror.
7. Try to reboard or climb onto it in order to get as much of your body out of the cold water as possible because treading water will ground to lose body heat sooner.
8. Do not waste energy and only signal when needed. Try to keep warm and stay strong<span />
Answer:
a) The module's acceleration in a vertical takeoff from the Moon will be 
b) Then we can say that a thrust of 
won't be able to lift off the module from the Earth because it's smaller than the module's weight (
).
Explanation:
a) During a vertical takeoff, the sum of the forces in the vertical axis will be equal to mass times the module's acceleration. In this this case, the thrust of the module's engines and the total module's weight are the only vertical forces. (In the Moon, the module's weight will be equal to its mass times the Moon's gravity acceleration)
Where:
thrust 
module's mass 
moon's gravity acceleration 
module's acceleration during takeoff
Then, we can find the acceleration like this:
The module's acceleration in a vertical takeoff from the Moon will be
b) To takeoff, the module's engines must generate a thrust bigger than the module's weight, which will be its mass times the Earth's gravity acceleration.
Then we can say that a thrust of won't be able to lift off the module from the Earth because it's smaller than the module's weight ().
The product of (wavelength) x (frequency) is always the same number ... the wave's speed.
So if the wavelength is somehow reduced to 1/4 its original length, the <em>frequency is immediately multiplied by 4</em> . That's the only way their product can remain the same.
Answer:
d) -4.0
Explanation:
The magnification of a lens is given by
where
M is the magnification
q is the distance of the image from the lens
p is the distance of the object from the lens
In this problem, we have
p = 50 cm is the distance of the object from the lens
q = 250 cm - 50 cm is the distance of the image from the lens (because the image is 250 cm from the obejct
Also, q is positive since the image is real
So, the magnification is
Answer:
4m
Explanation:
you divide 20m/s by 5 seconds
