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Arturiano [62]
2 years ago
9

PLS HELP

Physics
2 answers:
Amanda [17]2 years ago
7 0

V(final) = V(initial) + a•t

Take the numbers you know, pluggum in, and you should get 3.836 m/s .

Note: This is just the final speed. Without any direction information, there's no way to find the velocity.

Zepler [3.9K]2 years ago
5 0

Answer:

hmm first add 32  plus 53 plus 12 trust me and when you get the answer subtract 25

Explanation:

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Answer:

Option A

Explanation:

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3 years ago
an 1150kg elevator moving down speeds up at a rate of 3.5m/s. what is the tension in the supporting cables?
gtnhenbr [62]

Answer:

The tension force in the supporting cables is 7245N

Explanation:

There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:

F_{net} = F_g - F = m\cdot g - F\\

We are given the resulting acceleration along with the mass, i.e., we know the net force, allowing us to solve for F:

1150kg\cdot 3.5\frac{m}{s^2}= 1150kg \cdot 9.8\frac{m}{s^2}-F\\\implies F = 1150kg\cdot(9.8-3.5)\frac{m}{s^2}= 7245N

The tension force F in the supporting cables is 7245N


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