To solve this problem we will begin by applying the given relations of density in terms of mass and volume, and from this last value we will take its geometric measurement for a sphere (Approximation of a planet) From there we will find the radius of the planet. Finally we will make a comparison between the radius of the new planet and the radius of the earth to understand its proportion.
Defining the Volume variables we have to
Here
V= Volume
m = mass
=Density
For a spherical object the Volume is
PART A)
Equation we have
In this case the mass of new planet is 5.5times the mass of Earth,
Then,
The mass of the Earth is kg and the density is ,
Replacing we have that,
Therefore the radius of this new planet is
PART B) The value of radius of the Earth is
Then the relation between them is
Therefore the radius of the new planet in terms of radius of the Earth is
We know that tangential acceleration is related with radius and angular acceleration according the following equation:
at = r * aa
where at is tangential acceleration (in m/s2), r is radius (in m) aa is angular acceleration (in rad/s2)
So the radius is r = d/2 = 1.2/2 = 0.6 m
Then at = 0.6 * 5 = 3 m/s2
Tangential acceleration of a point on the flywheel rim is 3 m/s2
Explanation:
Displacement=Velocity×time
=24.7×16.00
=395.2m
Therefore the displacement within the time interval is 395.2m
2H2O2 ------> 2H2O +O2
because we're given one side with 2 hydrogens and 2 oxygens and another sie with 3 oxygens and 2 hydrogens. The hydrogens are balanced but the oxygens are not. You can't make the oxygen a three on the reactants side with a whole number so you multiply by 2.
Now you have 4 hydrogens and 4 oxygens on one side and 4 hydrogens and 4 oxygens on the other :)
Answer:
A conventional bomb releases most of its energy in the form of blast. Atomic bombs on the other hand, release 50 per cent energy as blast, 35 per cent as heat and 15 per cent as nuclear radiation.
Explanation:
A conventional bomb releases most of its energy in the form of blast. Atomic bombs on the other hand, release 50 per cent energy as blast, 35 per cent as heat and 15 per cent as nuclear radiation.