3 years ago

С какой скоростью велосипедист проходит закругление велотрека радиусом 25 м, если центростремительное ускорение при этом 4 м/с2?

Physics

1 answer:

irakobra [83]3 years ago

6 0

Explanation:

to determine light brightness

to determine planet compositition

to determine the ages of p

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Ainat [17]

Answer:

the answer might the number 2

Explanation:

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3 years ago

A man of mass 50kg ascends a flight of stairs 5m high in 5 seconds. If acceleration due to gravity is 10ms-2, the power expended

Setler79 [48]

The power expended is 500 W

Explanation:

First of all, we start by calculating the work done by the man in order to ascend: this is equal to the gravitational potential energy gained by the man, which is

$W=mg\Delta h$

where

m = 50 kg is the mass of the man

$g=10 m/s^2$ is the acceleration of gravity

$\Delta h = 5 m$ is the change in height

Substituting,

$W=(50)(10)(5)=2500 J$

Now we can calculate the power expended, which is given by

$P=\frac{W}{t}$

where

W = 2500 J is the work done

t = 5 s is the time elapsed

Substituting, we find

$P=\frac{2500}{5}=500 W$

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3 years ago

Andy has set a goal to be able to run 65 laps on the PACER by the end of the school year. This is an example of a ____.

lana66690 [7]

Answer:

The answer is long- term goal

Explanation:

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3 years ago

Which is correct help asap

Wittaler [7]

Answer:

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3 years ago

A particle of charge of +3.40 ✕ 10−6 C is 17.5 cm distant from a second particle of charge of −2.00 ✕ 10−6 C. Calculate the magn

Karolina [17]

Answer:

0.47 N

Explanation:

q1 = 3.4 x 10^-6 C

q2 = 2 x 10^-6 C

d = 17.5 cm = 0.175 m

The electrostatic force is given by

$F=\frac{Kq_{1}q_{2}}{d^{2}}$

$F=\frac{9\times10^{9}\times3.4\times 10^{-6}\times 2\times 10^{-6}}{0.175\times 0.175}$

F = 0.47 N

Thus, the force is 0.47 N.

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3 years ago