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hammer [34]
2 years ago
5

What is the force exerted on a charge of 2. 5 µC moving perpendicular through a magnetic field of 3. 0 × 102 T with a velocity o

f 5. 0 × 103 m/s? 3. 8 N 38 N 3. 8 × 105 N 3. 8 × 106 N.
Physics
1 answer:
emmasim [6.3K]2 years ago
5 0

As per the problem, the charge is of 2.5μC, moving in magnetic field 3\times10^{2} T and having velocity 5\times 10^{3} m/s, the force comes out to be 3.75N

<h3>what is magnetic force?</h3>

Magnetic force is the force experienced by the object inside the magnetic field or flowing current across the conductor. This force is caused due to the movement of charges.

The force exerted is magnetic force which is given as,

F= QVBsin\theta

here,

Q= charge

v= velocity

B= Magnetic field and

\theta=Angle of object from magnetic field

F=2.5\times10^{-6} \times 5\times10^{3} \times3\times10^{2}\times sin90

F=3.75N

To know more about Magnetic Force

brainly.com/question/13791875

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In separate experiments, a large number of particles (all with the same charge, but with a wide variety of masses and speeds) ar
likoan [24]

Answer:

  they have the same mass

Explanation:

The force applied by the field is a function of the charge and velocity, so the acceleration experienced by a particle will be dependent upon its mass. Particles in orbits with the same radius are exhibiting the same acceleration, so must have the same mass.

7 0
3 years ago
Determine the magnitude of the force between two 42 m-long parallel wires separated by 0.03 m, both carrying 6.3 A in the same d
xz_007 [3.2K]

Answer:

The magnitude of the force between the two parallel wires is 0.0111 N.

Explanation:

Given;

length of the two parallel wires, L = 42 m

distance between the two wires, r = 0.03 m

current in both wires, I₁, I₂ = 6.3 A

Therefore, the magnitude of the repulsive force between the two parallel wires is given by;

F = \frac{\mu_0 I_1I_2l}{2\pi r}\\\\where;\\\mu_0 \ is \ permeability \ of \ free \ space = 4\pi *10^{-7} \ T.m/A \\\\F = \frac{(4\pi *10^{-7})(6.3)^2(42)}{2\pi (0.03)}\\\\F =   0.0111 \ N

Therefore, the magnitude of the force between the two parallel wires is 0.0111 N.

6 0
3 years ago
A wire 3.22 m long and 7.32 mm in diameter has a resistance of 11.9 mΩ. A potential difference of 33.7 V is applied between the
Scorpion4ik [409]

Answer:

(a) Current is 2831.93 A

(b) 8.40A/m^2

(c) \rho =15.52\times 10^{-9}ohm-m

Explanation:

Length of wire l = 3.22 m

Diameter of wire d = 7.32 mm = 0.00732 m

Cross sectional area of wire

A=\pi r^2=3.14\times 0.00366^2=4.20\times 10^{-5}m^2

Resistance R=11.9mohm=11.9\times 10^{-3}ohm

Potential difference V = 33.7 volt

(A) current is equal to

i=\frac{V}{R}=\frac{33.7}{11.9\times 10^{-3}}=2831.93A

(B) Current density is equal to

J=\frac{i}{A}

J=\frac{2831.93}{4.20\times 10^{-5}}=8.40A/m^2

(c) Resistance is equal to

R=\frac{\rho l}{A}

11.9\times 10^{-3}=\frac{\rho \times 3.22}{4.20\times 10^{-5}}

\rho =15.52\times 10^{-9}ohm-m

4 0
3 years ago
If the sun had twice the mace how would that affect the gravitational force of the sun
daser333 [38]

Answer:  Gravity is the force that keeps planets in orbit around the Sun. Gravity alone holds us to Earth's surface.

Planets have measurable properties, such as size, mass, density, and composition. A planet's size and mass determines its gravitational pull.

A planet's mass and size determines how strong its gravitational pull is.

Models can help us experiment with the motions of objects in space, which are determined by the gravitational pull between them.

Explanation:

5 0
3 years ago
Whats the answer<br> ----------------------------
GenaCL600 [577]

Answer:

repel each other

Explanation:

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8 0
2 years ago
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