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hammer [34]
2 years ago
5

What is the force exerted on a charge of 2. 5 µC moving perpendicular through a magnetic field of 3. 0 × 102 T with a velocity o

f 5. 0 × 103 m/s? 3. 8 N 38 N 3. 8 × 105 N 3. 8 × 106 N.
Physics
1 answer:
emmasim [6.3K]2 years ago
5 0

As per the problem, the charge is of 2.5μC, moving in magnetic field 3\times10^{2} T and having velocity 5\times 10^{3} m/s, the force comes out to be 3.75N

<h3>what is magnetic force?</h3>

Magnetic force is the force experienced by the object inside the magnetic field or flowing current across the conductor. This force is caused due to the movement of charges.

The force exerted is magnetic force which is given as,

F= QVBsin\theta

here,

Q= charge

v= velocity

B= Magnetic field and

\theta=Angle of object from magnetic field

F=2.5\times10^{-6} \times 5\times10^{3} \times3\times10^{2}\times sin90

F=3.75N

To know more about Magnetic Force

brainly.com/question/13791875

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Answer:

calculating displacement.

Explanation:

It's not true that displacement and distance would be the same always. Displacement is always smaller than or equal to distance as it is the smallest path between the initial and final point whereas distance is the measure of the total path covered.

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2 years ago
Variations in the reactive properties of different organic molecules are most closely associated with _____.
azamat

Answer:

the presence or absence of functional groups

Explanation:

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7 0
2 years ago
Read 2 more answers
Calculate the mass of an object with a density of 102.5 g/mL and volume of 375 mL.
AveGali [126]

Answer:

38,437.5

Explanation:

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D =m/v

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3 years ago
The predictions of Rutherford's scattering formula failed to correspond with experimental data when the energy of the incoming a
Vera_Pavlovna [14]

Answer:

The radius of the gold nucleus is 7.1x10⁻¹⁵m

Explanation:

The nearest distance is:

r=\frac{kze^{2} }{mpV^{2} } (eq. 1)

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e = electron charge = 1.6x10⁻¹⁹C

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energy of the particle = 32 MeV = 5.12x10⁻¹²J

At the potential energy is zero, all the energy will be kinetic energy:

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Where

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Replacing in equation 1

r=\frac{9x10^{9}*79*(1.6x10^{-19})^{2}   }{2.56x10^{-12} } =7.1x10^{-15} m

8 0
2 years ago
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