What is the force exerted on a charge of 2. 5 µC moving perpendicular through a magnetic field of 3. 0 × 102 T with a velocity o
1 answer:
As per the problem, the charge is of 2.5μC, moving in magnetic field T and having velocity
m/s, the force comes out to be 3.75N
Magnetic force is the force experienced by the object inside the magnetic field or flowing current across the conductor. This force is caused due to the movement of charges.
The force exerted is magnetic force which is given as,
here,
Q= charge
v= velocity
B= Magnetic field and
=Angle of object from magnetic field
To know more about Magnetic Force
You might be interested in
Power is defined as the rate at which the body is doing work:
Work is defined as displacement done by the force times that displacement:
We know that we need 62N to move the box, so when we apply this force along the path of 10m we have done:
of work.
Now we just divide that by 5s to get how much power is required:
Work is defined as displacement done by the force times that displacement:
We know that we need 62N to move the box, so when we apply this force along the path of 10m we have done:
of work.
Now we just divide that by 5s to get how much power is required:
Answer:
0.67 s
Explanation:
This is a simple harmonic motion (SHM).
The displacement, , of an SHM is given by
A is the amplitude and is the angular frequency.
We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or radian.
From trigonometry, if A and B are complementary.
At ,
So
At ,
The period, , is related to
by