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baherus [9]
3 years ago
8

g If the x-component of a force vector is 5.69 newtons and its y-component is 8.00 newtons, then what is its magnitude?

Physics
2 answers:
vagabundo [1.1K]3 years ago
8 0

Answer:

Magnitude of resultant force will be 9.816 N      

Explanation:

We have given x-component of the force vector is 5.69 N

So x component F_x=5.69N

y component of force vector is 8 N

So y component will be F_Y=8N

We have to find the magnitude of the resultant force

Resultant force will be vector sum of x and y component of the forces

So F=F_xi+F_Yj=5.69i+8j

So resultant magnitude will be F=\sqrt{F_x^2+F_y^2}=\sqrt{5.69^2+8^2}=9.816N

So magnitude of resultant force will be 9.816 N

beks73 [17]3 years ago
4 0

Answer:

F = 9.82 N

Explanation:

given,

Force x-component = 5.69 N

Force y-component = 8 N

magnitude of force = ?

Resultant of force

F = \sqrt{F_x^2 + F_y^2}

F = \sqrt{5.69^2 + 8^2}

F = \sqrt{32.3761 + 64}

F = \sqrt{96.3761}

F = 9.82 N

Hence, the magnitude of force is equal to 9.82 N

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A negatively-charged particle is slowly moving as it enters a region that has a constant magnetic field. If the velocity of the
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no deflection and net force is zero. Moving in same direction and with same speed

Explanation:

Charge = negative

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3 years ago
crowbar of 5 metre is used to lift an object of 800 metre if the effort arm is 200cm calculate the force applied​
Klio2033 [76]

Answer:

 F = 5226.6 N

Explanation:

To solve a lever, the rotational equilibrium relation must be used.

We place the reference system on the fulcrum (pivot point) and assume that the positive direction is counterclockwise

         F d₁ = W d₂

where F is the applied force, W is the weight to be lifted, d₁ and d₂ are the distances from the fulcrum.

In this case the length of the lever is L = 5m, t the distance desired by the fulcrum from the weight to be lifted is

d₂ = 200 cm = 2 m

therefore the distance to the applied force is

          d₁ = L -d₂

         d₁ = 5 -2

         d₁= 3m

we clear from the equation

          F = W d₂ / d₁

          W = m g

          F = m g d₂ / d₁

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      F = 800 9.8 2/3

      F = 5226.6 N

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