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baherus [9]
3 years ago
8

g If the x-component of a force vector is 5.69 newtons and its y-component is 8.00 newtons, then what is its magnitude?

Physics
2 answers:
vagabundo [1.1K]3 years ago
8 0

Answer:

Magnitude of resultant force will be 9.816 N      

Explanation:

We have given x-component of the force vector is 5.69 N

So x component F_x=5.69N

y component of force vector is 8 N

So y component will be F_Y=8N

We have to find the magnitude of the resultant force

Resultant force will be vector sum of x and y component of the forces

So F=F_xi+F_Yj=5.69i+8j

So resultant magnitude will be F=\sqrt{F_x^2+F_y^2}=\sqrt{5.69^2+8^2}=9.816N

So magnitude of resultant force will be 9.816 N

beks73 [17]3 years ago
4 0

Answer:

F = 9.82 N

Explanation:

given,

Force x-component = 5.69 N

Force y-component = 8 N

magnitude of force = ?

Resultant of force

F = \sqrt{F_x^2 + F_y^2}

F = \sqrt{5.69^2 + 8^2}

F = \sqrt{32.3761 + 64}

F = \sqrt{96.3761}

F = 9.82 N

Hence, the magnitude of force is equal to 9.82 N

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One ring of radius a is uniformly charged with charge +Q and is placed so its axis is the x-axis. A second ring with charge –Q i
kati45 [8]

Answer:

The force exerted on an electron is 7.2\times10^{-18}\ N

Explanation:

Given that,

Charge = 3 μC

Radius a=1 m

Distance  = 5 m

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Put the value into the formula

E=1.0183\times10^{3}-1.064\times10^{3}

E=-0.045\times10^{3}\ N/C

We need to calculate the force exerted on an electron

Using formula of electric field

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F=E\times q

Put the value into the formula

F=-0.045\times10^{3}\times(-1.6\times10^{-19})

F=7.2\times10^{-18}\ N

Hence, The force exerted on an electron is 7.2\times10^{-18}\ N

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