A calorimeter has a heat capacity of 1265 J/oC. A reaction causes the temperature of the calorimeter to change from 22.34oC to 2

Question

4 years ago

14

5.12oC. How many joules of heat were released in
this process?

2 answers:

Ray Of Light [21] · Answer 1 · 2021-11-04T10:40:20+03:00

<h2>Heat released in this process is 3516.7 J</h2>

Explanation:

A calorimeter has a heat capacity of 1265 J/°C

Heat capacity of calorimeter = 1265 J/°C

A reaction causes the temperature of the calorimeter to change from 22.34°C to 25.12°C

Change in temperature = 25.12 - 22.34 = 2.78°C

Heat released = Heat capacity of calorimeter x Change in temperature

Heat released = 1265 x 2.78 = 3516.7 J

Heat released in this process is 3516.7 J

Novosadov [1.4K] · Answer 2 · 2021-11-04T12:25:47+03:00

Answer:

heat released is $3.51 \times 10^3 \ J.$

Explanation:

It is given that, heat capacity of calorimeter is, H = $1265 \ J/^0C.$

Also , initial temperature of calorimeter, $T_i=22.34^0C.$

final temperature of calorimeter, $T_f=25.12^oC.$

We know , Heat will release when it is positive.

So, heat released , Heat = $H \times(T_f-T_i)=1265\times(25.12-22.34)\\=3516.7 \ J=3.51\times 10^3\ J.$ .

Since it is positive. Therefore, heat released is $3.51 \times 10^3 \ J.$