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denpristay [2]
3 years ago
14

A calorimeter has a heat capacity of 1265 J/oC. A reaction causes the temperature of the calorimeter to change from 22.34oC to 2

5.12oC. How many joules of heat were released in
this process?
Physics
2 answers:
Ray Of Light [21]3 years ago
5 0
<h2>Heat released in this process is 3516.7 J</h2>

Explanation:

A calorimeter has a heat capacity of 1265 J/°C

Heat capacity of calorimeter = 1265 J/°C

A reaction causes the temperature of the calorimeter to change from 22.34°C to 25.12°C

Change in temperature = 25.12 - 22.34 = 2.78°C

Heat released = Heat capacity of calorimeter x Change in temperature

Heat released = 1265 x 2.78 = 3516.7 J

Heat released in this process is 3516.7 J

Novosadov [1.4K]3 years ago
5 0

Answer:

heat released is 3.51 \times 10^3 \ J.

Explanation:

It is given that, heat capacity of calorimeter is, H = 1265 \ J/^0C.

Also , initial temperature of calorimeter, T_i=22.34^0C.

final temperature of calorimeter, T_f=25.12^oC.

We know , Heat will release when it is positive.

So, heat released , Heat =H \times(T_f-T_i)=1265\times(25.12-22.34)\\=3516.7 \ J=3.51\times 10^3\ J..

Since it is positive. Therefore, heat released is 3.51 \times 10^3 \ J.

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