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3 years ago

I need help please it’s for a lab

Physics

1 answer:

krok68 [10]3 years ago

5 0

Answer:

idk

Explanation:

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What is a synonym for inertia?

RSB [31]

Answer:

ummmm probably.... inaction or inactivity

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3 years ago

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Problem 6.056 Air enters a compressor operating at steady state at 15 lbf/in.2, 80°F and exits at 275°F. Stray heat transfer and

vova2212 [387]

To solve this process it is necessary to consider the concepts related to the relations between pressure and temperature in an adiabatic process.

By definition the relationship between pressure and temperature is given by

$(\frac{P_2}{P_1})=(\frac{T_2}{T_1})^{(\frac{\gamma}{\gamma-1})}$

Here

P = Pressure

T = Temperature

$\gamma =$ The ratio of specific heats. For air normally is 1.4.

Our values are given as,

$P_1 = 15lb/in^2\\T_1= 80\°F = 299.817K\\T_2 =400\°F = 408.15K$

Therefore replacing we have,

$(\frac{P_2}{P_1})=(\frac{T_2}{T_1})^{(\frac{\gamma}{\gamma-1})}$

$(\frac{P_2}{15})=(\frac{408.15}{299.817})^{(\frac{1.4}{1.4-1})}$

Solving for $P_2,$

$P_2 = 15*(\frac{408.15}{299.817})^{(\frac{1.4}{1.4-1})}$

$P_2 = 44.15Lbf/in^2$

Therefore the maximum theoretical pressure at the exit is $44.15Lbf/in^2$

5 0

3 years ago

A local AM radio station broadcasts at a frequency of 696 KHz. Calculate the energy of the frequency at which it is broadcasting

bagirrra123 [75]

Answer:

$E=4.61\times 10^{-28}\ J$

Explanation:

Given that,

The frequency of local AM radio station, f = 696 KHz = 696000 Hz

We need to find the energy of the frequency at which it is broadcasting.

We know that,

Energy of a wave, E = hf

Where

h is Planck's constant

Put all the values,

$E=6.63\times 10^{-34}\times 696000\\\\=4.61\times 10^{-28}\ J$

So, the energy of the wave is equal to $4.61\times 10^{-28}\ J$ .

5 0

2 years ago

What is the difference between melting point and boiling point?

castortr0y [4]

Melting point is when a mass goes from solid to liquid, whereas boiling point is when a mass goes from liquid to gas. I hope this helps.

8 0

2 years ago

A car is traveling at 21.0 m/s. It slows to a stop at a constant rate over 5.00s. How far does the car travel during those 5.00

Doss [256]

Answer:

d = 105 m

Explanation:

Speed of a car, v = 21 m/s

We need to find the distance traveled by the dar during those 5 s before it stops. Let the distance is d. It can be calculated as :

d = v × t

d = 21 m/s × 5 s

d = 105 m

So, it will cover 105 m before it stops.

5 0

2 years ago