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Nutka1998 [239]
3 years ago
7

A 5.20-N force is applied to a 1.05-kg object to accelerate it rightwards across a friction-free surface. determine the accelera

tion.
Physics
2 answers:
Gnom [1K]3 years ago
7 0

Answer:

4.95 m/s/s

Explanation:

Upon neglecting air <u>resistance</u>, there are three forces acting upon the object. The up and <u>downforce</u> balance each other and the acceleration is caused by the <u>applied</u> force. The net force is 5.20 N, right (equal to the only rightward force - the applied force). So the <u>acceleration</u> of the object can be <u>computed</u> using Newton's second law.

a = Fnet / m = (5.20 N, right) / (1.05 kg) = 4.95 m/s/s, right

ZanzabumX [31]3 years ago
3 0

Explanation:

Newton's second law:

F = ma

5.20 N = (1.05 kg) a

a = 4.95 m/s²

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You are a member of an alpine rescue team and must project a box of supplies, with mass m, up an incline of constant slope angle
AlekseyPX

Answer:

v = \sqrt{2gh + \frac{2\mu_kgh}{tan\theta}}

Explanation:

When we push the box from the bottom of the incline towards the top then by work energy theorem we can say that

Work done by all the forces = change in kinetic energy of the system

- mgh - F_f (s) = 0 - \frac{1}{2}mv^2

here we know that

F_f = \mu_k mg cos\theta

also we know that the length of the incline is given as

s = \frac{h}{sin\theta}

now we have

- mgh - \mu_k mgcos\theta(\frac{h}{sin\theta}) = -\frac{1}{2}mv^2

so we have

v = \sqrt{2gh + \frac{2\mu_kgh}{tan\theta}}

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3 years ago
All electromagnetic waves
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Electromagnetic Waves:

Radio waves, television waves, and microwaves.

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3 years ago
A Net Force of 9.0 N acts through a distance of 3.0 m in a time of 3.0 s. The work done is?
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5 0
3 years ago
Read 2 more answers
Which statements are true concerning Newton's law of gravitation? The gravitational force is related to the mass of each object.
OLEGan [10]

Answer:

The gravitational force is related to the mass of each object.

The gravitational force is an attractive force.

Explanation:

Gravitational force is a long range force of attraction between any two masses.

Mathematically given as :

F=G.\frac{m_1.m_2}{r^2}

where:

m_1 & m_2 are the masses

r= distance between the center of mass of the two objects.

G= gravitational constant = 6.67\times 10^{-11} m^3.kg^{-1}.s^{-2}

From the above relation of eq. (1) it is clear that,

Gravitational force is inversely proportional to the square of the distance and directly proportional to the masses.

The mass of an object is independent of its size due to the fact that density may vary for different objects.

The force of gravity varies with height as:

\frac{g}{g_x} =(\frac{r_x}{r} )^2

where:

g=9.8\,m.s^{-2}

g_x= gravity at height r_x of the center of mass of the object from the center of mass of the earth.

and we know that force:

F=m\times g

where: m= mass of the object.

5 0
3 years ago
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