Answer:
The distance between the submarine is, d = 9933.3 m
Explanation:
Given data,
The speed of the submarine A and B, v = 5 m/s
Submarine A produces a pulse of sound to detect B at a distance, d = 10 km
= 10000 m
The speed of sound in water is, V = 1500 m/s
The time period to receive echo is given by the formula,
t = d / v
= 10000 / 1500
= 6.67 s
The distance between the submarine is given by the relation
d = 10000 - 2(v x t)
= 10000 - 2(5 x 6.67)
= 9933.3 m
Hence, the distance between the submarine is, d = 9933.3 m
Answer:
average emf induced in the coil is 1.57 x V
Explanation:
Given data
n = 10 turns per centimeter = 1000 m^-1
N = 5
cross-sectional area A = 5.0 cm2 = 5.0 x 10^-4 m²
current = 0.25 A
to find out
average emf induced in the coil
solution
we will find emf by the given formula
emf = - (μ×N×n×A×ΔI ) / t ..................1
here
μ = 4π x 10^-7 and
N = 10
n = 1000
A = 5.0 x 10^-4
ΔI = 0.25
t = 0.050
put all value in equation 1
emf = - (μ×N×n×A×ΔI ) / t
emf = - (4π x 10^-7 ×5 ×1000× 5.0 x 10^-4 × 0.25 ) / 0.050
emf = 1.57 x V
average emf induced in the coil is 1.57 x V
Answer:
D remove 1.5 ML of liquid.
Explanation:
Answer:
433.15K
Explanation:
(320°F − 32) × 5/9 + 273.15 = 433.15K