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Nutka1998 [239]
3 years ago
7

A 5.20-N force is applied to a 1.05-kg object to accelerate it rightwards across a friction-free surface. determine the accelera

tion.
Physics
2 answers:
Gnom [1K]3 years ago
7 0

Answer:

4.95 m/s/s

Explanation:

Upon neglecting air <u>resistance</u>, there are three forces acting upon the object. The up and <u>downforce</u> balance each other and the acceleration is caused by the <u>applied</u> force. The net force is 5.20 N, right (equal to the only rightward force - the applied force). So the <u>acceleration</u> of the object can be <u>computed</u> using Newton's second law.

a = Fnet / m = (5.20 N, right) / (1.05 kg) = 4.95 m/s/s, right

ZanzabumX [31]3 years ago
3 0

Explanation:

Newton's second law:

F = ma

5.20 N = (1.05 kg) a

a = 4.95 m/s²

You might be interested in
an ice skater starts with a velocity 2.25 m/s in a 50.0 degree direction after 8.33s she is moving 4.65 m/s in a 120 degree dire
svetoff [14.1K]

Answer:

-0.032 m/s^2

Explanation:

To answer the question, we just need to consider the motion along the horizontal direction.

The component of the initial velocity of the ice skater along the x-direction is:

u_x = u cos \theta =(2.25)(cos 50^{\circ})=1.45 m/s

where u = 2.25 m/s is the initial velocity and 50^{\circ} is the angle.

The component of the final velocity of the ice skater along the x-direction is

v_x = u cos \theta =(4.65)(cos 120^{\circ})=-2.33 m/s

where u = 4.65 m/s is the final velocity and 120^{\circ} is the angle.

The acceleration along the x-direction is given by

a_x=\frac{v_x-u_x}{t}

where

t = 120 s is the time

Substituting,

a=\frac{-2.33-(1.45)}{120}=-0.032 m/s^2

7 0
4 years ago
On a straight road, a car speeds up at a constant rate from rest to 20 m/s over a 5 second interval and a truck slows at a const
IceJOKER [234]

Answer:

a)

Explanation:

  • Since the car speeds up at a constant rate, we can use the kinematic equation for distance (assuming that the initial position is x=0, and choosing t₀ =0), as follows:

        x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}   (1)

  • Since the car starts from rest, v₀ =0.
  • We know the value of t = 5 sec., but we need to find the value of a.
  • Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:

       a_{c} =\frac{v_{fc}}{t} = \frac{20m/s}{5s} = 4 m/s2  (2)

  • Replacing a and t in (1):

       x_{fc} = v_{o}*t + \frac{1}{2}*a*t^{2}  = \frac{1}{2}*a*t^{2} = \frac{1}{2}* 4 m/s2*(5s)^{2} = 50.0 m.  (3)

  • Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
  • Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:

       a_{t} =\frac{-v_{to}}{t} = \frac{-20m/s}{10s} = -2 m/s2  (4)

  • Replacing v₀, at and t in (1), we have:

       x_{ft} = 20m/s*10.0s + \frac{1}{2}*(-2 m/s2)*(10.0s)^{2} = 200m -100m = 100.0m   (5)

  • Therefore, as the truck travels twice as far as the car, the right answer is a).
7 0
3 years ago
The threaded shaft of a bolt is 33 mm long and its pitch is
Nata [24]

Answer:

It would take 30 turns

Explanation:1.1 times 30=33

5 0
3 years ago
What do the vertical lines of the periodic table tell us?
Dafna11 [192]

Answer:

It tells us

Explanation:

The number of valence shell electrons in an element's atom that is measured by a vertical column in the periodic table.

8 0
3 years ago
Find the dimension of volume​
BlackZzzverrR [31]

Answer:

L^3

Explanation:

7 0
3 years ago
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