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Nutka1998 [239]
3 years ago
7

A 5.20-N force is applied to a 1.05-kg object to accelerate it rightwards across a friction-free surface. determine the accelera

tion.
Physics
2 answers:
Gnom [1K]3 years ago
7 0

Answer:

4.95 m/s/s

Explanation:

Upon neglecting air <u>resistance</u>, there are three forces acting upon the object. The up and <u>downforce</u> balance each other and the acceleration is caused by the <u>applied</u> force. The net force is 5.20 N, right (equal to the only rightward force - the applied force). So the <u>acceleration</u> of the object can be <u>computed</u> using Newton's second law.

a = Fnet / m = (5.20 N, right) / (1.05 kg) = 4.95 m/s/s, right

ZanzabumX [31]3 years ago
3 0

Explanation:

Newton's second law:

F = ma

5.20 N = (1.05 kg) a

a = 4.95 m/s²

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PLEASE HELP! Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an
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Explanation:

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3 years ago
a) Calculate the magnitude of displacement of the car in 40 seconds. b) During which part of the journey was the car acceleratin
Zielflug [23.3K]

Answer:

a)  600 meters

b) between 0 and 10 seconds, and between 30 and 40 seconds.

c) the average of the magnitude of the velocity function is 15 m/s

Explanation:

a) In order to find the magnitude of the car's displacement in 40 seconds,we need to find the area under the curve (integral of the depicted velocity function) between 0 and 40 seconds. Since the area is that of a trapezoid, we can calculate it directly from geometry:

Area \,\,Trapezoid=(\left[B+b]\,(H/2)\\displacement= \left[(40-0)+(30-10)\right] \,(20/2)=600\,\,m

b) The car is accelerating when the velocity is changing, so we see that the velocity is changing (increasing) between 0 and 10 seconds, and we also see the velocity decreasing between 30 and 40 seconds.

Notice that between 10 and 30 seconds the velocity is constant (doesn't change)  of magnitude 20 m/s, so in this section of the trip there is NO acceleration.

c) To calculate the average of a function that is changing over time, we do it through calculus, using the formula for average of a function:

Average\,of\,f(x)=\frac{1}{b-a} \int\limits^b_a {f(x)} \, dx

Notice that the limits of integration for our case are 0 and 40 seconds, and that we have already calculated the area under the velocity function (the integral) in step a), so the average velocity becomes:

Avearage=\frac{600\,\,m}{40\,\,s}= 15\,\,\frac{m}s}

7 0
3 years ago
A rocket burns fuel to create hot gases that explode violently out of the rocket engine. This explosion creates thrust. Thrust i
Lerok [7]

Answer:

Thrust due to fuel consumption must overcome gravitational force from the Earth to send the rocket up into space.

Explanation:

From the concept of Escape Velocity, derived from Newton's Law of Gravitation, definition of Work, Work-Energy Theorem and Principle of Energy Conservation, which is the minimum speed such that rocket can overcome gravitational forces exerted by the Earth, and according to the Tsiolkovski's Rocket Equation, which states that thrust done by the rocket is equal to the change in linear momentum of the rocket itself, we conclude that thrust due to fuel consumption must overcome gravitational force from the Earth to send the rocket up into space.

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A gardener mows a lawn with an old-fashioned push mower. The handle of the mower makes an angle of 320 with the surface of the l
Virty [35]

Answer:

N = 337.96 N

Explanation:

∅ = 32º

F = 249 N

m = 21 Kg

N = ?

We can apply:

∑ F = 0  (↑)

- Fy - W + N = 0   ⇒    N = Fy + W

⇒  F*Sin ∅ + m*g = N

⇒  N = (249 N*Sin32º) + (21 Kg*9.81 m/s²)

⇒  N = 337.96 N  (↑)

8 0
3 years ago
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