How far does a cyclist travel if she's going 6 m/s in 10 seconds?

You watch a distant lady driving nails into her front porch at a regular rate of 2 strokes per second. You hear the sound of the

Harlamova29_29 [7]

Since the lady is capable of delivering 2 strokes in 1 second, we know that it takes 0.5 seconds for one stroke of the hammer.

It is given that one more blow is heard even after she is seen as stopping hammering. This means that the sound from the last blow reached us a little later: 0.5 seconds after the last blow.

So, we know that time taken for the sound from the last blow to reach us t = 0.5 s

Speed of Sound is given as V = 340 m/s

Distance of the lady from us D = ?

Using the equation D = V.t, we get D = (340)(0.5) = 170 m

Thus, we can understand that the lady is 170 meters away from us.

3 0

3 years ago

a student standing between two walls shouts once.he hears the first echo after 3 seconds and the next after 5 seconds. calculate

Karolina [17]

Explanation:

It took $t_1 =1.5\:\text{s}$ for the sound to reach the 1st wall and at the same time time, the same sound took $t_2 = 2.5\:\text{s}$ to reach the 2nd wall. Assuming that the sound travels at 343 m/s, then let $x_1$ be the distance of the person to the 1st wall and $x_2$ be the distance to the 2nd wall. So the distance between the walls X is

$X = x_1 + x_2 = v_st_1 + v_st_2 = v_s(t_1 + t_2)$

$\:\:\:\:\:= (343\:\text{m/s})(4.0\:\text{s}) = 1372\:\text{m}$

6 0

2 years ago

A bowling ball is on the end of a rope of length 5 meters, the other end of which is attached to a hook in the ceiling. The ball

pogonyaev

Answer:

$a = 0\,\frac{m}{s^{2}}$

Explanation:

Let consider the following system, which is described in the image attached below and two reference axis, one parallel and the other perpendicular to the direction of motion. The corresponding equations of equilibrium are described herein:

$\Sigma F_{n} = T - m\cdot g \cdot \cos \theta = 0$