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Misha Larkins [42]
3 years ago
12

To cook food, a microwave oven converts electrical energy intoenergy A) electromagnetic B) heat C) mechanical D) nuclear

Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
5 0

To cook food, a microwave oven converts electrical energy into electromagnetic energy. (A)  Specifically, it pours high-power RADIO waves into the box.

Water molecules and fat molecules resonate (jiggle) with the radio waves, and the heat is generated IN THE FOOD.

I work with microwave radios.  

-- To communicate high-speed data over a distance of 5 to 10 miles, we use a radio transmitter with a power output of 0.07 watt .

-- To communicate high-speed data over distances up to 80 miles, we use a radio transmitter with a power output of 1 to 2 watts.

-- To heat up a chunk of leftover meatloaf, a microwave oven pumps radio waves into the box with a power output of 1200 to 1500 watts ! !

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Two sound waves of equal amplitude interference so that compression of one wave falls on the rarefaction of the other. Which sta
iris [78.8K]
<span>A. No sound is heard 
A*sin(wt)+(-A)*sin(wt)=0 - no sound

</span>
3 0
3 years ago
You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi
Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0
3 years ago
A car traveling at 22m/s is in an accident, and the 81 kg driver is brought to a stop in 1.4 s by in inflating airbag. What forc
larisa86 [58]
Here, F = m * a
F = m * v/t
Here, m = 81 Kg
v = 22 m/s
t = 1,4 s

Substitute their values, 
F = 81 * 22/1.4
F = 81 * 15.71
F = 1273 N
So, Closest value from your options is 1300 N

In short, Your Answer would be Option B

Hope this helps!
8 0
4 years ago
A charged particle enters into a uniform magnetic field such that its velocity vector is perpendicular to the magnetic field vec
Ugo [173]

Answer:

a circular path

Explanation:

In a magnetism field if a charged particle having a charge of magnitude '' enters  such that its velocity vector V is 90° to the direction of the magnetic field "B'', then it will experience a force, called Lorentz force F

F = V\times B

According to the property of cross-product, the Lorentz force (F) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path.

3 0
3 years ago
If a train going 60 m/s hits the brakes, and it takes the train 85 seconds to stop, what is
Anvisha [2.4K]

Question :-

  • If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?

Answer :-

  • Acceleration of Train is 0.70 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

\bigstar \:  \:  \:  \boxed { \sf{ \: Acceleration \:  =  \:  \dfrac{v \:  -  \: u}{t} \:  }} \\

Where ,

  • V denotes to Final Velocity .
  • U denotes to Initial Velocity .
  • T denotes to Time Taken .

Therefore , by Substituting the given values in the above Formula :-

\dag \:  \:  \:  \:  \sf{Acceleration \:  =  \:  \dfrac{Final  \: Velocity \:  -  \: Initial \: Velocity}{Time} } \\

\longmapsto \:  \:  \: \sf{Acceleration \:  =  \:  \dfrac{0 \:  -  \: 60}{85} } \\

\longmapsto \:  \:  \: \sf{Acceleration \:  =  \:  \dfrac{60}{85} } \\

\longmapsto \:  \:  \: \textbf {\textsf {Acceleration \:  =  \: 0.70 }}

Hence :-

  • Acceleration = 0.70 m/s² .

\underline {\rule {210pt} {4pt}}

Note :-

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7 0
2 years ago
Read 2 more answers
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