what aspect of receiver analog-to-digital conversion determines the maximum receive bandwidth of a direct digital conversion sdr
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Answer:
The intensity of laser 2 is 4 times of the intensity of laser 1.
Explanation:
The intensity in terms of electric field is given by :
E is electric field
It means,
In this problem, lasers 1 and 2 emit light of the same color, and the electric field in the beam of laser 1 is twice as strong as the e-field of laser 2.
Let E is electric field in the beam of laser 1 and E' is the electric field in the beam of laser 2. So,
We have,
E'=2E
So,
So, the intensity of laser 2 is 4 times of the intensity of laser 1.