what aspect of receiver analog-to-digital conversion determines the maximum receive bandwidth of a direct digital conversion sdr
1 answer:
You might be interested in
Answer:
v= 1.71 m/s
Explanation:
Given that
Distance between two successive crests = 4.0 m
λ = 4 m
T= 7 sec
T is the time between 3 waves.
3 waves = 7 sec
1 wave = 7 /3 sec
So t= 7/3 s
We know that frequency f
f= 1/t= 3/7 Hz
Lets take speed of the wave is v
v= f λ
f=frequency
λ=wavelength
v= 3/7 x 4 = 12 /7
v= 1.71 m/s
The force of frictions is opposed to relative motion.
The acceleration of the crate is approximately <u>2.937 m/s²</u>.
Reason:
The given parameters are;
The mass of the wood, m = 100 kg
The force which can move the wood, F = 588 N
Wood on wood static friction, = 0.5
Wood on wood kinetic friction, = 0.3
Solution;
The force of friction, , acting when the crate is moving is given as
follows;
= m × g ×
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore, we have;
= 100 × 9.81 × 0.3 = 294.3
The force of friction, = 294.3 N
The force with which the crate moves, F = 588 - 294.3 = 293.7
The force with which the crate moves, F = 293.7 N
Force = Mass, m × Acceleration, a
Therefore;
The acceleration of the crate, a ≈ <u>2.937 m/s²</u>.
Learn more about friction here: