what aspect of receiver analog-to-digital conversion determines the maximum receive bandwidth of a direct digital conversion sdr
1 answer:
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Answer:
a
The speed of wave is
b
The new speed of the two waves is
Explanation:
From the question we are told that
The mass of the string is
The length is
The tension is
Now the velocity of the first wave is mathematically represented as
Where is the linear density which is mathematically represented as
substituting values
So
Now given that the Tension, mass and length are constant the velocity of the second wave will same as that of first wave (reference PHYS 1100 )
Answer:
<em>Details in the explanation</em>
Explanation:
<u>Vertical Launch</u>
When an object is thrown vertically in free air (no friction), it moves upwards at its maximum speed while the acceleration of gravity starts to brake it. At a given time and height, the object stops in mid-air and starts to fall back to the launching point until reaching it with the same speed it was launched.
We are given an expression for the height of an object in function of time t
<em>Please note we have deleted the second 'squared' from the formula since it's incorrect and won't describe the motion of vertical launch.</em>
We now have to evaluate h for the following times, assuming h comes in feet
At t=1 sec
The object is at a height of 48 feet
At t=2 sec
The object is at a height of 64 feet. This is the maximum height the object will reach, as we'll see below
At t=3 sec
The object is at a height of 48 feet. We can clearly see it's returning from the maximum height and is going down
At t=4 sec
The object is at ground level and has returned to the launch point.