Ask question

Ask question

All categories

Marizza181 [45]

3 years ago

5

What is the term for substances that have several unpaired electrons and are strongly magnetic

1 answer:

Murljashka [212]3 years ago

8 0

Answer:

Scientific definitions for ferromagnetic

The property of being strongly attracted to either pole of a magnet. Ferromagnetic materials, such as iron, contain unpaired electrons, each with a small magnetic field of its own, that align readily with each other in response to an external magnetic field.

Explanation:

You might be interested in

Calculate the speed of a car if it covers the distance of 100m in 5seconds.

NeTakaya

Answer:

200m/s

Explanation:

$v = \frac{displacement}{time}$

8 0

2 years ago

Read 2 more answers

Insect A moves 5.0 m/min and insect B moves

mezya [45]

Answer:

insect B by 12m

Explanation:

30min = 1800s (times by 60)

5m/min x 30min = 150m

9cm/s x 1800s = 16,200cm = 162m

162m - 150m = 12m

6 0

2 years ago

Help what is the answer

Ainat [17]

Answer:

C

Explanation:

$F=k\dfrac{Q_1Q_2}{r^2}= \\\\(8.99 \times 10^9)\dfrac{(-2\times 10^{-4})(8\times 10^{-4})}{0.3^2}\approx 1.6\times 10^4 N$

Hope this helps!

5 0

2 years ago

The jumping gait of the kangaroo is efficient because energy is stored in the stretch of stout tendons in the legs; the kangaroo

Anna [14]

Answer:

the period T of whole motion should be twice the value for half at he bottom so T is 0.2sec.

w is angular frequency

formula:2π/T

now k is spring constant

F/R-->mw²

putting values:70*(2π/0.2)²

=4.9x10⁶

so we can say that SHM is not affected by the amplitude of the bounce.

6 0

3 years ago

Suppose a 49-N sled is resting on packed snow. The coefficient of kinetic friction is 0.11. If a person weighing 585 N sits on t

Andre45 [30]

Answer:

69.74 N

Explanation:

We are given that

Weight of sled=49 N

Coefficient of kinetic friction $,\mu_k=0.11$

Weight of person=585 N

Total weight==mg=49+585=634 N

We know that

Force needed to pull the sled across the snow at constant speed,F=Kinetic friction

$F=\mu_k N$

Where N= Normal=mg

$F=0.11\times 634=69.74 N$

Hence, the force is needed to pull the sled across the snow at constant speed=69.74 N

7 0

3 years ago