Find the mean, median, mode and range. Round answer to nearest tenth.
1 answer:
Answer:
The mean is 26.2
The median is 27
The mode is 32
The range is 38
Step-by-step explanation:
The mean is the average, to get it, add all of your values and divide the sum by the number of addends
The median is the middle number of the data set when order from least to greatest
The mode is the most occurred number
The range is the difference between the greatest number and the smallest number
The data:
9, 11, 12, 12, 14, 17, 25, 25, 27, 32, 32, 32, 33, 35, 41, 42, 47
∵ Their sum = 446
∵ They are 17 numbers
∵ Mean = sum ÷ number of data
∴ Mean = 446 ÷ 17 ≅ 26.2
The mean is 26.2
∵ The mean is the middle number of the data
∵ The middle of 17 numbers is the 9th one ( )
∵ The 9th one is 27
∴ Median = 27
The median is 27
∵ The mode is the most repeated number
∵ 32 is repeated three times (12 and 25 repeated twice only)
∴ Mode = 32
The mode is 32
∵ Range = greatest number - smallest number
∵ The greatest number is 47
∵ The smallest number is 9
∴ Range = 47 - 9 = 38
The range is 38
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3 pound of strawberry
Step-by-step explanation:
Given parameters:
Pounds of strawberry picked by Lexi =2
Pounds of strawberry eaten by Lexi sister =
Unknown:
Pound of strawberry Lexi's sister ate = ?
Solution:
This is a fraction word problem.
Let pound of strawberry eaten by Lexi's sister = K
We can establish that:
Pound of strawberry eaten by Lexi sister x K = Pound of strawberry picked by Lexi
Mathematically we have:
x K = 2
Learn more:
fractions brainly.com/question/1757979
#learnwithBrainly
K = =
K = 3 pound of strawberry
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
- a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°
- b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
- c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,
Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
- d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment
