Answer:
The empirical formula = molecular formula = C13H18O2
Explanation:
in 100% compound we have 75.6 % Carbon ( Molar mass = 12g/mole), 8.80% hydrogen ( Molar mass = 1.01 g/mole) and 15.5% Oxygen (Molar mass = 16.01 g/mole).
Carbon: 75.6g / 12 = 6.29
Hydrogen: 8.80/ 1 = 8.80
Oxygen: 15.5/ 16 = 0.97
⇒0.97 is the smallest so we divide everything through by 0.97
C: 6.29 / 0.97 = 6.48 ≈ 6.5
H: 8.80 /0.97 = 9
O: 0.97 / 0.97 = 1
To get rid of decimals, we multiply by 2
C: 6.5 x 2 = 13
H: 9 x 2 = 18
O: 1 x 2 = 2
The empirical formula = C13H18O2
13x 12g/mol + 18x1g/mol + 2x 16g/mol = 156 + 18 + 32 = 206g/mol which is the molar mass of ibuprofen
The empirical formula = molecular formula = C13H18O2
Answer: one molecule of O2.
Explanation: sweet i just took a guess but I believe that if 3 o2 molecules - 2 h2 molecules I think that its just basic maths and it is C because 3-2 = 1 and its o2 remaining, sorry if I’m wrong.
We are given the following equation:
y = y0 e^-0.0001216 t
where y = 1/5 y0, y0 is the original amount
So solving for time t:
1/5 y0= y0 e^-0.0001216 t
t = 13,235.51 years
So the human died about 13235.5 years ago
Answer:
The alkyl halide is secondary
The nucleophile is a poor nucleophile
The solvent is a protic solvent
The product is racemic
Explanation:
The reaction is shown in the image attached.
Alkyl halides undergo nucleophilic substitution by two mechanisms; SN1 and SN2. The particular mechanism that applies depends on;
I) structure of the alkyl halide
ii) nature of the nucleophile
iii) nature of the solvent
Looking at the reaction under review, we can see from the structure that the alkyl halide is a secondary alkyl halide. A secondary alkyl halide may undergo substitution via SN1 or SN2 mechanism depending on the conditions of the reaction.
If the nucleophile is poor, and the solvent is protic, SN1 mechanism is favoured over SN2 mechanism. Since CH3CH2OH is a poor nucleophile and ethanol is a protic solvent, we expect the reaction to proceed via SN1 mechanism leading to the formation of a racemic product.
The organic product is also shown in the second image attached.
I believe there would still be 3 protons in Lithium-8 because its usually the neutrons that are affected.
