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Alexxx [7]
3 years ago
12

Consider three elements A B and C all of which have atomic numbers of less then 20. The atomic number of A is x, and the atomic

number of B is three less than the atomic number of A
Element A forms cations with formula A+ and reacts with element C to form a solid substance with the formula AC

What is element A
Which group does element C belong to
Chemistry
1 answer:
Aleksandr-060686 [28]3 years ago
6 0

Answer:

LiH

A is lithium

group 1 or 7

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Complete combustion of 7.40 g of a hydrocarbon produced 22.4 g of CO2 and 11.5 g of H2O. What is the empirical formula for the h
cluponka [151]
<span>C2H5 First, you need to figure out the relative ratios of moles of carbon and hydrogen. You do this by first looking up the atomic weight of carbon, hydrogen, and oxygen. Then you use those atomic weights to calculate the molar masses of H2O and CO2. Carbon = 12.0107 Hydrogen = 1.00794 Oxygen = 15.999 Molar mass of H2O = 2 * 1.00794 + 15.999 = 18.01488 Molar mass of CO2 = 12.0107 + 2 * 15.999 = 44.0087 Now using the calculated molar masses, determine how many moles of each product was generated. You do this by dividing the given mass by the molar mass. moles H2O = 11.5 g / 18.01488 g/mole = 0.638361 moles moles CO2 = 22.4 g / 44.0087 g/mole = 0.50899 moles The number of moles of carbon is the same as the number of moles of CO2 since there's just 1 carbon atom per CO2 molecule. Since there's 2 hydrogen atoms per molecule of H2O, you need to multiply the number of moles of H2O by 2 to get the number of moles of hydrogen. moles C = 0.50899 moles H = 0.638361 * 2 = 1.276722 We can double check our math by multiplying the calculated number of moles of carbon and hydrogen by their respective atomic weights and see if we get the original mass of the hydrocarbon. total mass = 0.50899 * 12.0107 + 1.276722 * 1.00794 = 7.400185 7.400185 is more than close enough to 7.40 given rounding errors, so the double check worked. Now to find the empirical formula we need to find a ratio of small integers that comes close to the ratio of moles of carbon and hydrogen. 0.50899 / 1.276722 = 0.398669 0.398669 is extremely close to 4/10, so let's reduce that ratio by dividing both top and bottom by 2 giving 2/5. Since the number of moles of carbon was on top, that ratio implies that the empirical formula for this unknown hydrocarbon is C2H5</span>
3 0
3 years ago
Select True or False: Pi bonds are covalent bonds in which the electron density is concentrated above and below a plane containi
anzhelika [568]

Answer:

True

Explanation:

In pi bonds, the electron density concentrates itself between the atoms of the compound but are present on either side of the line joining the atoms. Electron density is found above and below the plane of the line joining the internuclear axis of the two atoms involved in the bond.

Pi bonds usually occur by sideways overlap of atomic orbitals and this leads to both double and triple bonds.

3 0
3 years ago
A 1.5L intraveneous (IV) solution contains 919 grams glucose (C6H12O6). What is the molarity of this solution?
AleksandrR [38]

Answer:

3.4 M

Explanation:

M = grams/molar mass = ans./volume(L)

M = 919/180 = ans./1.5

3 0
3 years ago
0.68 moles of calcium to calcium atoms​
Oksanka [162]

0.68 \: moles \: calcium \times  \frac{6.02 \times  {10}^{23} \: calcium \: atoms }{1 \: mole \: calcium} \\

The (( mole calcium ))s are simplified so the answer is based on the number of calcium atoms.

0.68 \times 6.02 \times  {10}^{23} = 68 \times  {10}^{ - 2} \times 602 \times  {10}^{ - 2} \times  {10}^{23} \\

= 68 \times 602 \times  {10}^{ - 4} \times  {10}^{23} = 40936 \times  {10}^{19} \\

calcium \: atoms = 40936 \times  {10}^{19}  \\

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

3 0
3 years ago
What is the mass of 10.0 cm the 3rd power of water
yKpoI14uk [10]

If you mean cubic cm, then it will be about 10 grams

5 0
3 years ago
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