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2 years ago

Please check my work!! is my answer correct?

Mathematics

2 answers:

harkovskaia [24]2 years ago

8 0

Yes your work is correct

myrzilka [38]2 years ago

8 0

According to me you are correct

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Help plz i need it :(

mr_godi [17]

Answer:

Step-by-step explanation:

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3 years ago

Identify the volume of the composite figure rounded to the nearest tenth. HELP PLEASE!!

nirvana33 [79]

Answer:

V = 115.3 ft³

Step-by-step explanation:

The left part of the figure shows a cube of side length 4.2 ft. The volume of a cube is V = s³, where s is the side length. Hence, the volume of this particular cube is V = (4.2 ft)³ = 74.088.

The volume of a pyramid is V = (1/3)(base area)(height).

Here V = (1/3)(4.2 ft)²(7 ft) = 41.16 ft³.

Summing up the two distinct areas, we get V = 41.16 ft³ + 74.088 ft³, or

V = 115.3 ft³ after rounding up to the nearest tenth.

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3 years ago

(4 X 3) X 2 please help me!! she needs help again

Gnoma [55]

Answer:

(4 x 3) x 2=
=12 x 2

=24

Step-by-step explanation:

3 0

1 year ago

Read 2 more answers

A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow

Mrrafil [7]

Answer:

$\displaystyle \frac{54}{5405}$ .

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

$\displaystyle \left(50\atop 5\right) = 2,118,760$ .

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

$\displaystyle \left( 28\atop 2\right) = 378$ .

Number of ways to choose 3 green candies out of a batch of 8:

$\displaystyle \left(8\atop 3\right)=56$ .

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

$\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168$ .

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

$\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}$ .

3 0

2 years ago

Can x in f(x) be replaced by another letter? For example f(a);Would that be the same thing?

Murljashka [212]

Answer:

Yes

Step-by-step explanation:

X is just an unknown variable which can be substituted as another variating condition. I.E Function of x can be written as Function of a. If no other condition is present.

5 0

2 years ago

Read 2 more answers