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Rasek [7]
3 years ago
7

What is the electron configuration of neptunium?

Chemistry
1 answer:
UkoKoshka [18]3 years ago
7 0
This is the electron configuration of neptunium:
<span>Rn 5f4 6d1 7s2
</span>or, if you want to complicate:
<span>1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s2 4f14 5d10 6p6 7s2 5f4 6d1
</span>Since there are 93 electrons, they make up 5f4 altogether.
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Dvinal [7]
When its in the northern hemisphere
5 0
3 years ago
how many moles of an ideal gas would occupy a 25.0 liter container when the temperature is 295 K and the pressure is 0.850 atm?
BlackZzzverrR [31]

Answer:

Required number of moles of ideal gas is 0.877 moles.

Explanation:

Pressure (P) = 0.850 atm

Temperature (T) = 295 K

Volume (V) = 25 ltr

Universal gas constant (R) = 0.0821

no of moles (n) = ?

we have the ideal gas equation as:

                           PV= nRT

                or, 0.850× 25 = n × 0.0821 × 295

                or, n = 0.877 moles

Hence the required number of moles of an ideal gas is 0.877 moles.

8 0
3 years ago
A solution contains 6.21 g of ethylene glycol dissolved in 25.0 g of water. If water has a boiling point elevation constant of 0
timurjin [86]
Calculate first the number of moles of ethylene glycol by dividing the mass by the molar mass.
                           n = (6.21 g ethylene glycol) / 62.1 g/mol
                              n = 0.1 mol
Then, calculate the molality by dividing the number of moles by the mass of water (in kg).
                           m = 0.1 mol/ (0.025 kg) = 4m
Then, use the equation,
                       Tb,f = Tb,i + (kb)(m)
Substituting the known values,
                       Tb,f = 100°C + (0.512°C.kg/mol)(4 mol/kg)
                          <em>Tb,f = 102.048°C</em>
5 0
2 years ago
Read 2 more answers
27/13Al+4/2He &gt;&gt;&gt;&gt; 30/15P+
Veseljchak [2.6K]

Answer

Explanation:

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

27/13Al+4/2He >>>> 30/15P+

5 0
3 years ago
What is the percent composition of chlorine in the compound Ba(ClO3)2?
tia_tia [17]

You're going to divide the mass of chlorine within the compound by the mass of the compound, and then multiply the result by 100 to get the answer

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2 years ago
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