Answer:
1040%
Explanation:
To solve this question we must convert the mass of Iron to moles in order to find limiting reactant. With limiting reactant we can find the theoretical moles of hydrogen and theoretical mass:
Percent yield = Actual yield (5.40g) / Theoretical yield * 100
<em>Moles Fe -Molar mass: 55.845g/mol-:</em>
10.3g * (1mol / 55.845g) = 0.184 moles of Fe will react.
For a complete reaction of these moles there are necessaries:
0.184 moles Fe* ( 3 mol H2SO4 / 2 mol Fe) = 0.277 moles H2SO4.
As there are 14.8 moles of the acid, <em>Fe is limiting reasctant.</em>
The moles of H2 produced are:
0.184 moles Fe* ( 3 mol H2 / 2 mol Fe) = 0.277 moles H2
The mass is:
0.277 moles H2 * (2.016g/mol) = 0.558g H2
Percent yield is:
5.40g / 0.558g * 100 = 1040%
It is possible the experiment wasn't performed correctly
1 significant figure, because there is no decimal after the zero the zero doesn't count.
Radioactive material obeys 1st order decay kinetics,
For 1st order reaction, we have
k =
where, k = rate constant of reaction
Given: Initial conc. 100, Final conc. = 6.25, t = 18.9 hours
∴ k =
= 0.1467 hours^(-1)
Now, for 1st order reactions: half life =
= 4.723 hours.
Mg gained mass because it went from being a single element (on the reactant side) to being a molecule (on the product side).
Answer:
Volume of NCl3 is 3L
Explanation:
Avogadro states: All gases at the same volume under temperature and pressure constant have the same number of moles.
The chemical equation is:
3Cl2(g) + N2(g) → 2NCl3(g)
Where 3 moles of chlorine reacts with 1 mole of nitrogen to produce 2 moles of NCl3.
But using Avogadros law we can say:
3L of chlorine and 1L of nitrogen produce 2L of Nitrogen trichloride.
3L of chlorine and 1L of nitrogen: 4L (The stoichiometric mixture)
That means, volume of NCl3 produced is 3L
