Answer:
the correct answer is B
Explanation:
Subduction: they present if or if two Convergent edges or subduction zones (destructive edges). Where two plates collide, due to having movements with opposite directions, the denser one sinks below the less dense one along what is known as the subduction zone; the subducting plate goes into the mantle, heating up and partially melting generating magma that rises to the surface. A subduction zone is characterized by deformation, volcanism, mountain formation, metamorphism, seismic activity, and significant mineral deposits.
This phenomenon occurs between oceanic plates or between a continental and an oceanic plate, since when there is a difference in density they subduct.
In the event that the edges of two continental plates collide, it would be OBDUCTION, which is another phenomenon other than subduction. mantle does not produce the correct subduction process, as the movement must be absorbed in some way, this is carried out by vertically deforming both plates, which are joined by a suture area, forming an inner mountainous belt and Suffering, in addition, numerous earthquakes. This process is very important, since it is the one that has given rise to the highest mountain ranges on Earth and is a very active process at present (Ex: Los Alpes, Los Montes Urales and Montes Himalaya).
The first one would be it
Answer:
0.85 mole
Explanation:
Step 1:
The balanced equation for the reaction of CaCl2 to produce CaCO3. This is illustrated below:
When CaCl2 react with Na2CO3, CaCO3 is produced according to the balanced equation:
CaCl2 + Na2CO3 -> CaCO3 + 2NaCl
Step 2:
Conversion of 85g of CaCO3 to mole. This is illustrated below:
Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol
Mass of CaCO3 = 85g
Moles of CaCO3 =?
Number of mole = Mass /Molar Mass
Mole of CaCO3 = 85/100
Mole of caco= 0.85 mole
Step 3:
Determination of the number of mole of CaCl2 needed to produce 85g (i.e 0. 85 mole) of CaCO3.
This is illustrated below :
From the balanced equation above,
1 mole of CaCl2 reacted to produced 1 mole of CaCO3.
Therefore, 0.85 mole of CaCl2 will also react to produce 0.85 mole of CaCO3.
From the calculations made above, 0.85 mole of CaCl2 is needed to produce 85g of CaCO3
Products are copper+ aluminium chloride
reactants are aluminium+copper chloride
