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Eva8 [605]
3 years ago
9

Peut-on être exact sans être précis?

Chemistry
1 answer:
Evgesh-ka [11]3 years ago
8 0

Answer:

I think you can.

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The atom shown below is?
Volgvan

Answer:

Explanation:

Not likely to form any bonds because in it's last she'll it has 8 electrons and is therefore stable

8 0
2 years ago
How many of each component are shown in the diagram? Check all that apply. one battery two switches two batteries two resistors
VikaD [51]
<h3>In reference to the diagram attached </h3><h3>Answer:</h3>

one battery, two switches, and three light bulbs

Explanation:

  • A circuit is an arrangement that shows the flow of electrons from a current source such as a battery.
  • The diagram shows a circuit that contains one battery, two switches, and three light bulbs.
  • The switches serves to close the circuit when necessary.
  • The battery supplies current to the circuit.
  • The light bulbs are used for lighting.

8 0
3 years ago
Read 2 more answers
Can someone answer dis:
SVEN [57.7K]

Answer:

If we subtract the atomic number from the atomic mass: atomic mass - atomic number = number of protons + number of neutrons - number of protons. Thus we get the number of neutrons present in an atom when we subtract the atomic number from the atomic mass.

Explanation: hope this helps???

7 0
3 years ago
Read 2 more answers
Estimate the enthalpy change for the combustion of one mole of acetylene, C2H2, to form carbon dioxide and water vapor. BE(C?H)
tia_tia [17]

Answer:

ΔH rxn =  -1010 kJ/molC₂H₂

Explanation:

To obtain the enthalpy change for a reaction from bond energies what we do is to make an inventory of the bonds broken and formed for the balanced chemical reaction:

C₂H₂ + 5/2O₂   ⇒   2CO₂ + H₂O

Bond Broken                                    Bonds Formed

2 C-H + 1 C≡C + 5/2 O=O                4C=O + 2 H-O

Enthalpy bonds broken:

2 mol (456 kJ/mol)+ 1 mol (962 kJ/mol) + 5/2 mol (499 kJ/mol)  =  3121.5 kJ

Enthalpy bond formed:

4 mol (802 kJ/mol) + 2 mol (462 kJ/mol) = 4132.0 kJ

ΔH rxn = H broken - H formed =  3121.5 kJ - 4132.0 kJ = - 1010  kJ (per mol C₂H₂ )

4 0
3 years ago
Calculate the pH of a 0.010 M NaNO2 solution.
ryzh [129]

Answer:

Calculate the pH of 0.010 M HNO2 solution. The K, for HNO2 is 4.6 x 104

Answer: pH = 2.72

3 0
2 years ago
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