The specific heat capacity of this chunk of metal is equal to 0.32 J/g°C.
<u>Given the following data:</u>
- Quantity of energy = 400 Joules
- Initial temperature = 20°C
To determine the specific heat capacity of this chunk of metal:
<h3>
The formula for quantity of heat.</h3>
Mathematically, quantity of heat is given by the formula;

<u>Where:</u>
- Q represents the quantity of heat.
- m represents the mass of an object.
- c represents the specific heat capacity.
- ∅ represents the change in temperature.
Making c the subject of formula, we have:

Substituting the given parameters into the formula, we have;

Specific heat, c = 0.32 J/g°C.
Read more on specific heat here: brainly.com/question/2834175
Answer:
The cathode is the electrode where the reduction takes place.
Explanation:
Cell has three components:
an electrolyte and two electrodes which is a cathode and an anode.
Electrolyte is usually solution of the water or other solvents in which the ions are dissolved.
<u>In electrolytic cell:</u>
Negatively charged electrode is the cathode where the process of reduction takes place.
Positively charged electrode is the anode where the process of oxidation takes place.
<u>In galvanic cell:</u>
Positively charged electrode is the cathode where the process of reduction takes place.
Negatively charged electrode is the anode where the process of oxidation takes place.
<u>So, the correct answer is - The cathode is the electrode where the reduction takes place.</u>
Answer:
B. oxidation; reduction
Explanation:
A voltaic cell is electro-chemical cell in which chemical energy is converted into electrical energy.
1. This cell utilizes chemical reaction to generate electric.\
2. there two electrode anode and cathode
3. At Anode oxidation occurs
4. At cathode reduction occurs
5. chemical is present in the cell which is electrolyte which completes the circuit of the voltaic cell.
- oxidation is the process in which there is loss of electrons
- Reduction is the process in which there is gain of electrons
___________________________________________________
Based on above discussion
At anode oxidation takes place
At cathode reduction takes place.
Hence, correct option is B. oxidation; reduction
Answer:0.00000009
Explanation:
9.11 × (1/1000000000)=0.00000009