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Nitella [24]
3 years ago
15

I need help on 5 and 6

Chemistry
2 answers:
morpeh [17]3 years ago
3 0
I think that the answers are 16 and 1, I hope this helps!! Good Luck!!
Masteriza [31]3 years ago
3 0
5 is 32 and 6 is 2 that is the answer
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4. If 175 undecayed nuclei remain from a sample of 2800 nuclei, how many half-
Irina18 [472]

Answer:

X = 4

Explanation:

Start 2800

End 175

175 = 2800x(0.5)^X

175/2800 = 0.5^X

0.0625 = 0.5^X

log(0.5 x) = log(0.0625)

x · log(0.5) = log(0.0625)

-0.301x = -1.204

x = -1.204/-0.301

x = 4

8 0
3 years ago
How many moles are in 3.01 x 10^23 atoms of zinc?
Lerok [7]

Answer:

<h2>0.5 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{3.01 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{3.01}{6.02}  \\  = 0.5

We have the final answer as

<h3>0.5 moles</h3>

Hope this helps you

6 0
2 years ago
Be sure to answer all parts. The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. H2(g) + CO2(g) ⇌ H2O(g) +
nikklg [1K]

<u>Answer:</u>

<u>For 1:</u> The value of \Delta G for the chemical equation is -24.636 kJ/mol

<u>For 2:</u> The value of \Delta G for the chemical equation is -20.925 kJ/mol

<u>Explanation:</u>

For the given chemical equation:

H_2(g)+CO_2(g)\rightleftharpoons H_2O(g)+CO(g)

  • <u>For 1:</u>

To calculate the \Delta G for given value of equilibrium constant, we use the relation:

\Delta G=-RT\ln K_p      .....(1)

where,

\Delta G = ? kJ/mol

R = Gas constant = 8.314J/K mol

T = temperature = 2000 K

K_p = equilibrium constant in terms of partial pressure = 4.40

Putting values in above equation, we get:

\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (4.40)\\\\\Delta G=-24636.12J/mol

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -24636.12 J/mol = -24.636 kJ/mol

Hence, the value of \Delta G for the chemical equation is -24.636 kJ/mol

  • <u>For 2:</u>

The expression of K_p for the given chemical equation is:

K_p=\frac{p_{CO}p_{H_2O}}{p_{H_2}p_{CO_2}}

We are given:

p_{CO}=1.18atm\\p_{H_2O}=0.66atm\\p_{CO_2}=0.82atm\\p_{H_2}=0.27atm

Putting values in above equation, we get:

K_p=\frac{1.18\times 0.66}{0.27\times 0.82}\\\\K_p=3.52

Now, calculating the value of \Delta G by using equation 1:

R = Gas constant = 8.314J/K mol

T = temperature = 2000 K

K_p = equilibrium constant in terms of partial pressure = 3.52

Putting values in equation 1, we get:

\Delta G=-(8.314J/Kmol)\times 2000K\times \ln (3.52)\\\\\Delta G=-20925.68J/mol

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, -20925.68 J/mol = -20.925 kJ/mol

Hence, the value of \Delta G for the chemical equation is -20.925 kJ/mol

3 0
3 years ago
Read 2 more answers
Compared to the charge of a proton, the charge of all electron has
Kay [80]
<span>Answer: option (4) the same magnitude and the opposite sign.
</span>
Justification:
<span /><span /><span>
</span><span>1) Electrons are negative particles thar are around the nucleus of the atom (in regions called orbitals).
</span>
<span /><span /><span>
2) Protons are positive particles that are inside the nuclus of the atom.
</span><span />

<span>3) The nucleus of the atom has the same number of protons as electrons are in the orbitals of the atom.
</span>
<span /><span /><span>
4) The atoms are neutral (neither positive nor negative) because there are the same number of electrons and protons and their charge are of the same magnitude but different sign: (+) + (-) = 0: positive + negative = neutral.</span>
6 0
3 years ago
Read 2 more answers
1-Propynyllithium reacts with (R,R)-2,3-dimethyloxacyclopropane in a stereoselective reaction. Draw a curved arrow mechanism and
QveST [7]

Answer:

Reference image attached

Explanation:

Please see the attached image.

6 0
2 years ago
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