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3 years ago

(I will give brainliest, ONLY if its correct!)

Chemistry

2 answers:

ryzh [129]3 years ago

7 0

Answer:

easy

Explanation:

In physics and chemistry, the law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time. This law means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.

LekaFEV [45]3 years ago

3 0

Answer:

- Energy is not created or destroyed

- Energy only transforms

Explanation:

Law of conservation of energy. It constitutes the first principle of thermodynamics and states that the total amount of energy in any isolated system (without interaction with any other system) remains unchanged over time, although such energy can be transformed into another form of energy.

The law of conservation of energy states that nothing exists and can not exist capable of generating energy, there is neither can exist anything capable of making energy disappear and finally if it is observed that the amount of energy varies, it will always be possible to attribute said variation to an exchange of energy with some other body or with the surrounding environment.

Energy is the ability of bodies or systems of bodies to perform a job. Every system that passes from one state to another produces physical or chemical phenomena that are nothing more than manifestations of some transformation of energy, since this can occur in different forms: kinetic, potential, electrical, mechanical, chemical. Whenever an amount of one class of energy is produced, an exactly equivalent amount of another class or classes should be consumed.

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Components of crude oil can be separated through a process called _____.

Drupady [299]

Answer:

Components of crude oil can be separated through a process called <u><em>fractional distillation</em></u>.

Explanation:

Fractional distillation can be described as a method of distillation in which a liquid mixture is separated based on the different boiling points of the components present in the mixture. The components of crude oil have different boiling temperatures hence, they can be separated by the process of fractional distillation.

The fractionating column has high temperatures at the bottom so components with high temperatures are separated at the bottom. The upper columns have lower temperatures. Components with lower boiling temperatures get separated at the upper columns.

3 0

2 years ago

Answer the following Question Down Below...

bonufazy [111]

The mass number of the atom is 21, the atomic number is 9, and the element is Fluorine. There are 9 protons, 9 electrons, 12 neutrons, and the elemental symbol is F.

<h3>Properties of an atom</h3>

For every atom:

Protons and neutrons are located in the nucleus and the addition of both equals the mass number of atoms.
Electrons are located outside the nucleus, in orbitals.
Neutral atoms have the same number of electrons and protons

In the diagram:

Number of electrons = 9

Number of protons = 9

Number of neutrons = 12

Mass number = 12 + 9

= 21

Atomic number = number of protons

= 9

Element with atomic number 9 = Fluorine

Symbol of the element = F

More on atoms can be found here: brainly.com/question/1566330

#SPJ1

5 0

1 year ago

5. All of the following statement describes compounds, EXCEPT?

Sveta_85 [38]

Answer:

Explanation:

Compounds cannot be separated by any physical means.

3 0

3 years ago

Read 2 more answers

3. After 7.9 grams of sodium are dropped into a bathtub full of water, how many grams of hydrogen gas are released?

Pavel [41]

Answer:

3) About 0.35 grams of hydrogen gas.

4) About 65.2 grams of aluminum oxide.

Explanation:

Question 3)

We are given that 7.9 grams of sodium is dropped into a bathtub of water, and we want to determine how many grams of hydrogen gas is released.

Since sodium is higher than hydrogen on the activity series, sodium will replace hydrogen in a single-replacement reaction for sodium oxide. Hence, our equation is:

$\displaystyle \text{Na} + \text{H$_2$O}\rightarrow \text{Na$_2$O}+\text{H$_2$}$

To balance it, we can simply add another sodium atom on the left. Hence:

$\displaystyle 2\text{Na} + \text{H$_2$O}\rightarrow \text{Na$_2$O}+\text{H$_2$}$

To convert from grams of sodium to grams of hydrogen gas, we can convert from sodium to moles of sodium, use the mole ratios to find moles in hydrogen gas, and then use hydrogen's molar mass to find its amount in grams.

The molar mass of sodium is 22.990 g/mol. Hence:

$\displaystyle \frac{1\text{ mol Na}}{22.990 \text{ g Na}}$

From the chemical equation, we can see that two moles of sodium produce one mole of hydrogen gas. Hence:

$\displaystyle \frac{1\text{ mol H$_2$}}{2\text{ mol Na}}$

And the molar mass of hydrogen gas is 2.016 g/mol. Hence:

$\displaystyle \frac{2.016\text{ g H$_2$}}{1\text{ mol H$_2$}}$

Given the initial value and the above ratios, this yields:

$\displaystyle 7.9\text{ g Na}\cdot \displaystyle \frac{1\text{ mol Na}}{22.990 \text{ g Na}}\cdot \displaystyle \frac{1\text{ mol H$_2$}}{2\text{ mol Na}}\cdot \displaystyle \frac{2.016\text{ g H$_2$}}{1\text{ mol H$_2$}}$

Cancel like units:

$=\displaystyle 7.9\cdot \displaystyle \frac{1}{22.990}\cdot \displaystyle \frac{1}{2}\cdot \displaystyle \frac{2.016\text{ g H$_2$}}{1}$

Multiply. Hence:

$=0.3463...\text{ g H$_2$}$

Since we should have two significant values:

$=0.35\text{ g H$_2$}$

So, about 0.35 grams of hydrogen gas will be released.

Question 4)

Excess oxygen gas is added to 34.5 grams of aluminum and produces aluminum oxide. Hence, our chemical equation is:

$\displaystyle \text{O$_2$} + \text{Al} \rightarrow \text{Al$_2$O$_3$}$

To balance this, we can place a three in front of the oxygen, four in front of aluminum, and two in front of aluminum oxide. Hence:

$\displaystyle3\text{O$_2$} + 4\text{Al} \rightarrow 2\text{Al$_2$O$_3$}$

To convert from grams of aluminum to grams of aluminum oxide, we can convert aluminum to moles, use the mole ratios to find the moles of aluminum oxide, and then use its molar mass to determine the amount of grams.

The molar mass of aluminum is 26.982 g/mol. Thus:

$\displaystyle \frac{1\text{ mol Al}}{26.982 \text{ g Al}}$

According to the equation, four moles of aluminum produces two moles of aluminum oxide. Hence:

$\displaystyle \frac{2\text{ mol Al$_2$O$_3$}}{4\text{ mol Al}}$

And the molar mass of aluminum oxide is 101.961 g/mol. Hence: $\displaystyle \frac{101.961\text{ g Al$_2$O$_3$}}{1\text{ mol Al$_2$O$_3$}}$

Using the given value and the above ratios, we acquire:

$\displaystyle 34.5\text{ g Al}\cdot \displaystyle \frac{1\text{ mol Al}}{26.982 \text{ g Al}}\cdot \displaystyle \frac{2\text{ mol Al$_2$O$_3$}}{4\text{ mol Al}}\cdot \displaystyle \frac{101.961\text{ g Al$_2$O$_3$}}{1\text{ mol Al$_2$O$_3$}}$

Cancel like units:

$\displaystyle= \displaystyle 34.5\cdot \displaystyle \frac{1}{26.982}\cdot \displaystyle \frac{2}{4}\cdot \displaystyle \frac{101.961\text{ g Al$_2$O$_3$}}{1}$