Bromide ions donates an electron in redox reactions.
<u>Explanation:</u>
- In these redox reactions, the halide ions like bromide donates a pair of electrons and acts as a reducing agents, but itself gets oxidized to bromine.
- In this process, the oxidation state of bromide ion is increased from -1 to 0 oxidation state, that is Br⁻ (-1) to Br₂ (0), thus reduces the compound and oxidizes by itself.
- Bromide ion is a strong reducing agent, thereby reduces sulfuric acid which changes to sulfur di oxide, but this doesn't happen in the case of chloride and fluoride ions as they are not having that much capacity like bromide and iodide ions.
The maximum amount of XeF4 that could be produced is 0.5 moles.
XeF4 = Xe (g) 2 F2 (g) (g)
Xe and F2 have a mole ratio of 1:2. Because of this, the reaction would be limited by F2 when there is 1 mole of Xe and 1 mole of F2.
<h3>What is mole ratio?</h3>
The mole ratio is the ratio of any two compounds' mole amounts that are present in a balanced chemical reaction.
A comparison of the ratios of the molecules required to accomplish the reaction is given by the balancing chemical equation.
A mole ratio is a conversion factor used in chemical reactions to link the mole quantities of any two compounds. A conversion factor's numbers are derived from the balanced chemical equation's coefficients.
To learn more about mole ratio from the given link:
brainly.com/question/14425689
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