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3 years ago

What will happen to the equilibrium of this reaction if HCl gas is injected into the system?

Chemistry

1 answer:

AlekseyPX3 years ago

3 0

Answer:this is called "LeChatelier's Principle"

.. "a system at equilibrium will shift in the direction to reduced an applied stress"

you have this

.. H2(g) + Cl2(g) <---> 2 H2O

if you add H2, the reaction while shift right to consume some of that extra H2.this is called "LeChatelier's Principle"

.. "a system at equilibrium will shift in the direction to reduced an applied stress"

you have this

.. H2(g) + Cl2(g) <---> 2 H2O

if you add H2, the reaction while shift right to consume some of that extra H2.

Explanation:

You might be interested in

g Find the ∆Hrxn for the reaction: 3C(s)+4H2(g) →C3H8(g) Using these reactions with known ∆H’s: C3H8(g) + 5O2(g) → 3CO2(g) + 4H2

slava [35]

<u>Answer:</u> The $\Delta H^o_{rxn}$ for the reaction is -104.7 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The chemical equation for the formation of propane follows:

$3C(s)+4H_2(g)\rightarrow C_3H_8(g)$ $\Delta H^o_{rxn}=?$

The intermediate balanced chemical reaction are:

(1) $C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)$ $\Delta H_1=-2043kJ$

(2) $C(s)+O_2(g)\rightarrow CO_2(g)$ $\Delta H_2=-393.5kJ$ ( × 3)

(3) $2H_2(g)+O_2(g)\rightarrow 2H_2O(g)$ $\Delta H_3=-483.6kJ$ ( × 2)

The expression for enthalpy of the reaction follows:

$\Delta H^o_{rxn}=[1\times (-\Delta H_1)]+[3\times \Delta H_2]+[2\times \Delta H_3]$

Putting values in above equation, we get:

$\Delta H^o_{rxn}=[(1\times (-(-2043))+(3\times (-393.5))+(2\times (-483.6))]=-104.7kJ$

Hence, the $\Delta H^o_{rxn}$ for the reaction is -104.7 kJ.

5 0

4 years ago

Molecules of sugar are attracted to each other and form crystals. If you place sugar in water, the crystals break apart, but the

suter [353]

Answer:

Explanation:

So here's the thing . Sugar molecule is a molecular solid . It a relatively weak molecule

We all know the formula of glucose ( which is a sugar type molecule ) which is C12 H22 O 11 . This is basically bonded together by dipole dipole forces ( remember that this force of attraction is weak ) .on the other hand you have the solution ( which is usually water) .water is held by strong attraction forces known as hydrogen bonding .since this type of bonding is greater than dipole dipole forces .therefore when glucose is dropped in water . water is easily able to obercome the forces that are keeping the glucose molecule intact . therefore the molecule dissolves and breaks into pieces. Hope this helps

3 0

3 years ago

Which of the following contains the greatest mass of oxygen?

Art [367]

Answer:

letter d

Explanation:

hope it's help you

5 0

3 years ago

The chemist discovers a more efficient catalyst that can produce ethyl butyrate with a 78.0% yield. How many grams would be prod

Vedmedyk [2.9K]

The grams that would be produced from 7.70 g of butanoic acid and excess ethanol is 7.923grams

calculation

Step 1: write the chemical equation for the reaction

CH3CH2CH2COOH + CH3CH2OH → CH3CH2CH2COOCH2CH3 +H2O

step 2: find the moles of butanoic acid

moles= mass/ molar mass

= 7.70 g/ 88 g/mol=0.0875 moles

Step 3: use the mole ratio to determine the moles of ethyl butyrate

moles ratio of CH3CH2CH2COOH :CH3CH2CH2COOCH2CH3 is 1:1 therefore the moles of CH3CH2CH2COOCH2CH3 = 0.0875 x78/100=0.0683moles

step 4: find mass = moles x molar mass

= 0.0683 moles x116 g/mol=7.923grams

5 0

3 years ago

Read 2 more answers

This pendulum is suspended on a string. The balanced forces of gravity and the tension force within the string are holding the p

GuDViN [60]

Answer:

The pendulum will begin to swing in the direction of the unbalanced force

Explanation:

The action of an unbalanced force on a pendulum will cause the pendulum to go into oscillation.

It must be stated that an unbalanced force causes acceleration of an object, in the direction of that force. Hence, unbalanced forces always set an object in motion.

5 0

3 years ago