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3 years ago

What is the name of the green segment in the hyperbola below?

Mathematics

1 answer:

Burka [1]3 years ago

4 0

Answer:

Option (A).

Step-by-step explanation:

In the figure attached a hyperbola has been given with a line passing through vertices.

By the definition,

"Major axis of a hyperbola is a line that passes through the center, foci and vertices of the hyperbola."

Therefore, green segment in the given hyperbola will be Major axis.

Option (A) will be the answer.

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Which fractions are equivalent to 15/20

Digiron [165]

Answer:

$\frac{3}{4}$ , $\frac{30}{40}$ , $\frac{45}{60}$ , $\frac{60}{80}$ ....e.t.c are all equivalent fractions

Step-by-step explanation:

For the answer you need to know bout equivalent fractions

TO find equivalent fractions you have to multiply the numerator and denominator by the same amount

E.x. $\frac{15}{20}=\frac{(15)(2)}{(20)(2)} =\frac{30}{40}$

Therefore $\frac{30}{40}$ is an equivalent fraction

8 0

3 years ago

There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro

elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that $\mu = 20.1, \sigma = 5.1$ .

You scored 24 on Exam A. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{24 - 20.1}{5.1}$

$Z = 0.76$

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that $\mu = 1031, \sigma = 215$ .

You scored 1167 on Exam B, s:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1167 - 1031}{215}$

$Z = 0.632$

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0

3 years ago

Boris bought 5 CDs that were each the same price. Including sales tax, he paid a total of $59.50. Each CD had a tax of $0.70. wh

Taya2010 [7]

Answer:

$8.40

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Please Help image below with question

djyliett [7]

I think it’s 128 or 64

5 0

3 years ago

Read 2 more answers

Please help if so thank you And explain

Naddika [18.5K]

Answer:

x = 34°

Step-by-step explanation:

Given AC and BD are perpendicular bisectors, we can say that at point E, there are 4 right angles [perpendicular bisectors intersect to create 4 90 degree angles].

Now, if we look at the triangle AED, we know that it is a right triangle, meaning that angle E is a right angle.

Also,

We know sum of 3 angles in a triangle is 180 degrees. Thus, we can write:

∠A + ∠E + ∠D = 180

<em>Note: Angle A and Angle D are just the half part of the diagram. More exactly we can write:</em>

∠EAD + ∠ADE + ∠DEA = 180

Given,

∠EAD = 56

∠DEA = 90

We now solve:

∠EAD + ∠ADE + ∠DEA = 180

56 + ∠ADE + 90 = 180

146 + ∠ADE = 180

146 + x = 180

x = 180 - 146

x = 34°

4 0

3 years ago