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3 years ago

Jackson earns nine dollars per hour walking dogs right in equation to find Jackson’s earnings M for any number of hours h

Mathematics

2 answers:

ElenaW [278]3 years ago

7 0

Answer:

$9 = 1hr

32hr=???

Step-by-step explanation:

1 x 32 = 32

9 x 32 = 288

natka813 [3]3 years ago

3 0

Answer:

Step-by-step explanation:

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Austin got a raise. Their hourly wage was increased from $18.00 to $20.50. What was the percent increase in Austin’s wage to the

agasfer [191]

Answer:

option 3)

14% approx

Step-by-step explanation:

Given data

Initial= $18.00

final =$20.50

% increase= final - initial/initia *100

% increase= 20.50-18.0/18*100

% increase=2.5/18*100

% increase=0.138*100

% increase=13.8%

Hence the increase is 13.8%

=14% approx

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3 years ago

Determine which number is a solution of the inequality. j+8 ≤ 8; 0, 1, 2

Troyanec [42]

Answer:

The solution to the inequality is 0.

7 0

3 years ago

Whats the awnser to the image that is selected?????

VikaD [51]

Answer:

30 units

Step-by-step explanation:

In order to find the length of the 3rd side of the triangle, the hypotenuse, you can use the Pythagorean Theorem. Using this method, you get 5^2+12^2=169. The square root of 169 is 13.

5 + 12 + 13 = 30 units.

7 0

2 years ago

Let T be the plane-2x-2y+z =-13. Find the shortest distance d from the point Po=(-5,-5,-3) to T, and the point Q in T that is cl

GaryK [48]

Answer:

d=10u

Q(5/3,5/3,-19/3)

Step-by-step explanation:

The shortest distance between the plane and Po is also the distance between Po and Q. To find that distance and the point Q you need the perpendicular line x to the plane that intersects Po, this line will have the direction of the normal of the plane $n=(-2,-2,1)$ , then r will have the next parametric equations:

$x=-5-2\lambda\\y=-5-2\lambda\\z=-3+\lambda$

To find Q, the intersection between r and the plane T, substitute the parametric equations of r in T

$-2x-2y+z =-13\\-2(-5-2\lambda)-2(-5-2\lambda)+(-3+\lambda) =-13\\10+4\lambda+10+4\lambda-3+\lambda=-13\\9\lambda+17=-13\\9\lambda=-13-17\\\lambda=-30/9=-10/3$

Substitute the value of $\lambda$ in the parametric equations:

$x=-5-2(-10/3)=-5+20/3=5/3\\y=-5-2(-10/3)=5/3\\z=-3+(-10/3)=-19/3\\$

Those values are the coordinates of Q

Q(5/3,5/3,-19/3)

The distance from Po to the plane

$d=\left| {\to} \atop {PoQ}} \right|=\sqrt{(\frac{5}{3}-(-5))^2+(\frac{5}{3}-(-5))^2+(\frac{-19}{3}-(-3))^2} \\d=\sqrt{(\frac{5}{3}+5))^2+(\frac{5}{3}+5)^2+(\frac{-19}{3}+3)^2} \\d=\sqrt{(\frac{20}{3})^2+(\frac{20}{3})^2+(\frac{-10}{3})^2}\\d=\sqrt{\frac{400}{9}+\frac{400}{9}+\frac{100}{9}}\\d=\sqrt{\frac{900}{9}}=\sqrt{100}\\d=10u$