the answer is C because the air balloon is going down meaning that negative
I control the pressure in my upper body whenever I feel like breathing ...
an urge that typically grabs me several times each day.
-- When I want to inhale, I move my diaphragm down. This expands my
chest cavity, reducing the pressure in it, and atmospheric pressure then
causes outside air to pour into my lungs.
-- When I want to exhale, I move my diaphragm up. This contracts my
chest cavity, increasing the pressure in it, and the compressed air in my
lungs then pours out, into the lower pressure of the surrounding atmosphere.
This is a hydraulic system, and these systems rely on the incompressible nature of fluids to transmit pressure through the fluid equally. Therefore, the pressure on the wide side of the U-tube (the side with the car) must be equal to the pressure on the narrow side of the U-tube. We begin by calculating the pressure on the wider side:
Pressure on wide side = pressure due to car + pressure due to difference in height of oil
The pressure by the car is calculated using:
Pressure = force / area
P = 12,000 / (π * 0.18²)
P = 118 kPa
While the pressure due to the oil is given by:
Pressure = density * gravitational field strength * height
P = 800 * 9.81 * 1.2
P = 9.4 kPa
Pressure on wide side:
118 + 9.4 = 127.4 kPa
Pressure on the narrow side will be given by:
Pressure = force / area
Force = area * pressure
Force = (π * 0.05²)(127,000)
Force = 997 Newtons
The force required is about 1 kN
This question is stated in a complicated way, but all the information we need is right there waiting to be untangled.
We'll start the clock when Todd arrives. At that time:
-- Kate has 5 done. Todd has none yet. Todd is 5 units behind.
From then on:
-- The clock is running. Kate adds 4 an hour to her total. Todd adds 5 an hour.
-- She started out 5 ahead of Todd when he arrived, but Todd does 1 more than Kate every hour.
-- So Kate's 'lead' shrinks by 1 every hour.
-- So <em>Todd will catch up with Kate</em> <em>in 5 hours</em>.
That's the answer to the question ... How long ? It doesn't ask us how many stockings have been filled, but that's easy for us to figure out:
-- Kate had 5 done when the clock started. She fills 4 every hour. After 5 hours, she has (5 x 4) = 20 more filled, and a total of 25 ready to sell.
-- Todd started out with none done. He fills 5 every hour. After 5 hours, he has (5 x 5) = 25 filled and ready to sell. He has caught up with Kate in 5 hours.
Answer:0.5
Explanation:
Given
Piece of taffy slams in to sticks to another identical piece and stuck into it.
Let m be the mass of taffy and u be the initial velocity of taffy and v be the final velocity of system.
Conserving momentum
![mu=2mv](https://tex.z-dn.net/?f=mu%3D2mv)
![v=\frac{u}{2}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bu%7D%7B2%7D)
Initial kinetic energy![=\frac{mu^2}{2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bmu%5E2%7D%7B2%7D)
Final Kinetic Energy![=\frac{2m(\frac{u}{2})^2}{2}=\frac{mu^2}{4}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B2m%28%5Cfrac%7Bu%7D%7B2%7D%29%5E2%7D%7B2%7D%3D%5Cfrac%7Bmu%5E2%7D%7B4%7D)
change in kinetic energy ![\Delta K.E.=\frac{mu^2}{2}-\frac{mu^2}{4}=\frac{mu^2}{4}](https://tex.z-dn.net/?f=%5CDelta%20K.E.%3D%5Cfrac%7Bmu%5E2%7D%7B2%7D-%5Cfrac%7Bmu%5E2%7D%7B4%7D%3D%5Cfrac%7Bmu%5E2%7D%7B4%7D)
change in kinetic energy will contribute in heat energy
thus fraction of kinetic energy converted in to heat ![=\frac{heat\ energy}{Initial\ kinetic\ Energy} =\frac{\frac{mu^2}{4}}{\frac{mu^2}{2}}=\frac{1}{2}=0.5](https://tex.z-dn.net/?f=%3D%5Cfrac%7Bheat%5C%20energy%7D%7BInitial%5C%20kinetic%5C%20Energy%7D%20%3D%5Cfrac%7B%5Cfrac%7Bmu%5E2%7D%7B4%7D%7D%7B%5Cfrac%7Bmu%5E2%7D%7B2%7D%7D%3D%5Cfrac%7B1%7D%7B2%7D%3D0.5)