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AnnyKZ [126]
3 years ago
12

An object attached to an ideal spring oscillates with an angular frequency of 2.81 rad/s. the object has a maximum displacement

at t = 0.00 s of 0.232 m. if the force constant (spring constant is 29.8 n/m, what is the potential energy stored in the mass-spring system when t = 1.42 s?
Physics
1 answer:
NikAS [45]3 years ago
4 0
Ω = 2.81
A = 0.232
k = 29.8

x = A cos(ωt + Ф)

at t = 0:
x = A = A cos(ωt + Ф) = A cos(Ф)
Ф = 0

at t = 1.42, with Ф = 0:
x = A cos(ωt) 

U = 1/2 k x² = 1/2 k [A cos(ωt)]²
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Answer:

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r=-\frac{15}{2\pi}t+\frac{168}{2\pi}

E=-\frac{d\phi}{dt}=-\frac{d(B\pi r^2)}{dt}=-2\pi rB\frac{dr}{dt}

E=-2\pi(-\frac{5}{2\pi}t+\frac{168}{2\pi})B\times -\frac{15}{2\pi}

t=8 s

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Answer:

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