We have: v = d/t
From the expression, we conclude speed is indirectly proportional to speed.
So, the car which will take longer time must have the smallest speed. Among all the options Car C has the smallest speed. So, it would be your answer.
In short, Your Answer would be Option C) Car C will take longer time than any other.
Hope this helps!
Answer:
dolphins and wolfs very easy
Explanation:
This question involves the concepts of the law of conservation of momentum and velocity.
The velocity of the eight ball is "5.7 m/s".
According to the law of conservation of momentum:
![m_1u_1+m_2u_2=m_1v_1+m_2v_2](https://tex.z-dn.net/?f=m_1u_1%2Bm_2u_2%3Dm_1v_1%2Bm_2v_2)
where,
m₁ = mass of number three ball = 5 g
m₂ = mass of the eight ball = 6 g
u₁ = velocity of the number three ball = 3 m/s
u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)
v₁ = final velocity of the three number ball = - 5 m/s
v₂ = final velocity of the eight ball = ?
Therefore,
(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)
![v_2=\frac{34\ g.m/s}{6\ g}\\\\](https://tex.z-dn.net/?f=v_2%3D%5Cfrac%7B34%5C%20g.m%2Fs%7D%7B6%5C%20g%7D%5C%5C%5C%5C)
<u>v₂ = 5.7 m/s</u>
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Learn more about the law of conservation of momentum here:
brainly.com/question/1113396?referrer=searchResults
Answer:
![U(r)=-\frac{Gm_Emr^2}{2R^3_E}](https://tex.z-dn.net/?f=U%28r%29%3D-%5Cfrac%7BGm_Emr%5E2%7D%7B2R%5E3_E%7D)
Explanation:
We are given that
Gravitational force=![F_g=\frac{Gm_Emr}{R^3_E}](https://tex.z-dn.net/?f=F_g%3D%5Cfrac%7BGm_Emr%7D%7BR%5E3_E%7D)
r=0,U(0)=0
We know that
Gravitational potential energy=![-\int F_gdr](https://tex.z-dn.net/?f=-%5Cint%20F_gdr)
![U(r)=-\int\frac{Gm_Emr}{R^3_E}dr](https://tex.z-dn.net/?f=U%28r%29%3D-%5Cint%5Cfrac%7BGm_Emr%7D%7BR%5E3_E%7Ddr)
![U(r)=-\frac{Gm_Em}{R^3_E}\times \frac{r^2}{2}+C](https://tex.z-dn.net/?f=U%28r%29%3D-%5Cfrac%7BGm_Em%7D%7BR%5E3_E%7D%5Ctimes%20%5Cfrac%7Br%5E2%7D%7B2%7D%2BC)
Substitute r=0 ,U(0)=0
![0=0+C](https://tex.z-dn.net/?f=0%3D0%2BC)
![C=0](https://tex.z-dn.net/?f=C%3D0)
Substitute the value
![U(r)=-\frac{Gm_Emr^2}{2R^3_E}](https://tex.z-dn.net/?f=U%28r%29%3D-%5Cfrac%7BGm_Emr%5E2%7D%7B2R%5E3_E%7D)
You know that when the displacement is equal to the amplitude (A), the velocity is zero, which implies that the kinetic energy (KE) is zeero, so the total mechanical energy (ME) is the potential energy (PE).
And you know that the potential energy, PE, is [ 1/2 ] k (x^2)
Then, use x = A, to calculate the PE in the point where ME = PE.
ME = PE = [1/2] k (A)^2.
At half of the amplitude, x = A/2 => PE = [ 1/2] k (A/2)^2
=> PE = [1/4] { [1/2]k(A)^2 } = .[1/4] ME
So, if PE is 1/4 of ME, KE is 3/4 of ME.
And the answer is 3/4