1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Artemon [7]
3 years ago
15

Gel electrophoresis is a technique used to separate nucleic acids by their _______.

Physics
1 answer:
ss7ja [257]3 years ago
6 0
<h2>Answer: size</h2>

Gel electrophoresis is called to the  technique used by scientists for analytical purposes, in life sciences laboratories to separate macromolecules (DNA, RNA, and proteins from various sources).

The process consists of separating the molecules according to their <u>size</u> and <u>electric charge</u>. This is done with a gel (a gelatinous substance extracted from seaweed, called <em>agarose</em>) of controllable porosity placed in an ionic buffer environment. This is how the gel acts as a molecular sieve that separates larger molecules from the smaller ones, because each molecule has different size and charge and will move through the gel at different speeds.

That is, the smaller molecules move more quickly through the gel while the larger ones are left behind.

You might be interested in
In a cyclotron, the orbital radius of protons with energy 300 keV is 16.0 cm . You are redesigning the cyclotron to be used inst
Archy [21]

Answer:

16 cm

Explanation:

For protons:

Energy, E = 300 keV

radius of orbit, r1 = 16 cm

the relation for the energy and velocity is given by

E = \frac{1}{2}mv^{2}

So, v = \sqrt{\frac{2E}{m}}   .... (1)

Now,

r = \frac{mv}{Bq}

Substitute the value of v from equation (1), we get

r = \frac{\sqrt{2mE}}{Bq}

Let the radius of the alpha particle is r2.

For proton

So, r_{1} = \frac{\sqrt{2m_{1}E}}{Bq_{1}}    ... (2)

Where, m1 is the mass of proton, q1 is the charge of proton

For alpha particle

So, r_{2} = \frac{\sqrt{2m_{2}E}}{Bq_{2}}    ... (3)

Where, m2 is the mass of alpha particle, q2 is the charge of alpha particle

Divide equation (2) by equation (3), we get

\frac{r_{1}}{r_{2}}=\frac{q_{2}}{q_{1}}\times \sqrt{\frac{m_{1}}{m_{2}}}

q1 = q

q2 = 2q

m1 = m

m2 = 4m

By substituting the values

\frac{r_{1}}{r_{2}}=\frac{2q}}{q}}\times \sqrt{\frac{m}}{4m}}=1

So, r2 = r1 = 16 cm

Thus, the radius of the alpha particle is 16 cm.

8 0
3 years ago
Read 2 more answers
15. What is a thermograph?
Genrish500 [490]

Answer: A device that uses infrared sensors.

Explanation:

8 0
3 years ago
Read 2 more answers
If the final speed of an object as is strikes the ground is 77 m/s and it was in the air for 6.5 seconds. What was the initial d
azamat

Answer:

The answer to your question is: 13.2 m/s

Explanation:

final speed (fs) = 77 m/s

t = 6.5 s

gravity (g) = 9.81 m/s2

initial speed (is) = ?

Formula

fs = is + gt     from this equation we clear "is" = fs - gt

Substitution                         is = 77 - (9,81)(6.5)

Process                               is = 77 - 63.8

                                            is = 13.2 m/s

8 0
3 years ago
You have a grindstone (a disk) that is 95.2 kg, has a 0.399 m radius, and is turning at 93 rpm, and you press a steel axe agains
olya-2409 [2.1K]

Answer:

angular acceleration is -0.2063  rad/s²

Explanation:

Given data

mass m = 95.2 kg

radius r = 0.399 m

turning ω = 93 rpm

radial force N  = 19.6 N

kinetic coefficient of friction  μ = 0.2

to find out

angular acceleration

solution

we know frictional force that is = radial force × kinetic coefficient of friction

frictional force = 19.6 × 0.2

frictional force = 3.92 N

and

we know moment of inertia  that is

γ =  I ×α = frictional force × r

so

γ  = 1/2 mr²α

α  = -2f /mr

α  = -2(3.92) /95.2 (0.399)

α  = - 7.84 / 37.9848 = -0.2063

so angular acceleration is -0.2063  rad/s²

3 0
3 years ago
Three cars (car F, car G, and car H) are moving with the same velocity when the driver suddenly slams on the brakes, locking the
Nastasia [14]

Answer:

Car H

Explanation:

Frictional force is a resistant force. It is given as:

F = u*m*g

Where u = coefficient of friction

m = mass

g = acceleration due to gravity

From the formula above, we see that frictional force is dependent on the mass of object and the coefficient of friction.

Since they all have the same tires, the coefficient of friction between the tire and the floor is the same for each car. Acceleration due to gravity, g, is constant.

The only factor that determines the frictional force of each car is the mass. Hence, the more the mass, the more the frictional force.

So, the most massive car will have the most frictional force and hence, will come to a stop quicker than the others. The least massive car will have the least frictional force and so, will take a longer time to stop.

5 0
3 years ago
Other questions:
  • Identify the false statement: Select one:
    12·2 answers
  • Otis watches a cooking show on making mayonnaise. The chef dissolves salt and sugar in vinegar. She mixes in an egg yolk, and th
    9·2 answers
  • A 2.0-kg mass (mA) and a 4.0-kg mass (mB) are connected to a lightweight cord that passes over a frictionless pulley. The pulley
    10·1 answer
  • PLEASE HELP I WILL GOVE BRAINLIEST TO FIRST CORRECT ANSWER!!!!!
    14·1 answer
  • A worker at the top of a 588-m-tall television transmitting tower accidentally drops a heavy tool. If air resistance is negligib
    8·1 answer
  • The side length of a 243-gram copper cube is 3 centimeters. Use this information to write a model for the radius of a copper sph
    8·1 answer
  • What are the two outcomes for a proto star?
    11·1 answer
  • A car travels at a speed of 30 mph.How far dose the car travel in 2 hours
    14·1 answer
  • A wire 25.0cm long lies along the z-axis and carries a current of 9.00A in the positive +z-direction. The magnetic field is unif
    10·1 answer
  • An object is thrown upward with an initial velocity of 32.1 m/s. When the object reaches it maximum height, it is true of the ac
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!