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zepelin [54]
4 years ago
8

Based on relative bond strengths, classify these reactions as endothermic (energy absorbed) or exothermic (energy released):

Physics
2 answers:
algol134 years ago
5 0

Answer:

The correct answer is

Endothermic:

AB+C-->AC+B

A2+C2-->2AC

B2+C2-->2BC

Exothermic:

A+BC-->AB+C

A2+B2-->2AB

Explanation:

Trust Me

VashaNatasha [74]4 years ago
4 0
Based on relative bond strengths, classify these reactions as endothermic (energy absorbed) or exothermic (energy released):
Endothermic 
B2+C2-->2BC 
A2+C2-->2AC 
<span>A2+B2-->2AB</span>

Exothermic 
AB+C-->AC+B 
A+BC-->AB+C 

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Solve the equation<br> (2.40 x 10^7)* (3.10 x 10-5^-5)
Mariulka [41]

Explanation:

(2.40 × 10⁷) × (3.10 × 10⁻⁵)

(2.40 × 3.10) × (10⁷ × 10⁻⁵)

7.44 × 10²

7 0
4 years ago
PLEASE HELP ME GET THIS RIGHT
alukav5142 [94]

Explanation:

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7 0
2 years ago
A rocket with a mass of 62,000 kg (including fuel) is burning fuel at the rate of 150 kg/s and the speed of the exhaust gases is
mezya [45]

Answer:

h≅ 58 m

Explanation:

GIVEN:

mass of rocket M= 62,000 kg

fuel consumption rate =  150 kg/s

velocity of exhaust gases v= 6000 m/s

Now thrust = rate of fuel consumption×velocity of exhaust gases

=6000 × 150 = 900000 N

now to need calculate time t = amount of fuel consumed÷ rate

= 744/150= 4.96 sec

applying newton's law

M×a= thrust - Mg

62000 a=900000- 62000×9.8

acceleration a= 4.71 m/s^2

its height after 744 kg of its total fuel load has been consumed

h= \frac{1}{2}at^2

h= \frac{1}{2}4.71\times4.96^2

h= 58.012 m

h≅ 58 m

4 0
3 years ago
What makes some chemical bonds more stable than others
Juliette [100K]

it occurs when the energy of the combination has lower energy than the separated atoms

4 0
3 years ago
Find the average velocity of the car during the time last three second interval. Answer in units of m/s.
Pani-rosa [81]

Answer:

<u>Average Velocity:</u>

When a body covers some displacement moving from point A to B, in a given time,t. Then dividing the total distance covered by the time taken to complete the displacement is called as the average velocity of that car.

We can calculate the average velocity of car by subtracting the initial displacement of a body,s₁ from  the final displacement position of the body, s₂. And then dividing by the initial time,t₁ been subtracted from the final time,t₂.

  • Δv=x₂-x₁/t₂-t₁,

We will get the required results, now if we want to obtain the results in the final three seconds then, we can have the following explanation to that as given.

Explanation:

Lets say, that we have the car moving for 10 seconds and then it stops at the eleventh second of the trip on final position, of the displacement. Then we divide the whole trips into small segments, as we will have the different velocity at each interval but, the velocity is unknown at the last 3 seconds is unknown=?.  

  • Total time taken, Δt= 11 seconds,
  • Then lets say the velocity at the 8th second is , v=25 m/s,then
  • Δv=x₂-(25)/11-0,⇒Δv=x₂-25/11,
3 0
3 years ago
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