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zepelin [54]
3 years ago
8

Based on relative bond strengths, classify these reactions as endothermic (energy absorbed) or exothermic (energy released):

Physics
2 answers:
algol133 years ago
5 0

Answer:

The correct answer is

Endothermic:

AB+C-->AC+B

A2+C2-->2AC

B2+C2-->2BC

Exothermic:

A+BC-->AB+C

A2+B2-->2AB

Explanation:

Trust Me

VashaNatasha [74]3 years ago
4 0
Based on relative bond strengths, classify these reactions as endothermic (energy absorbed) or exothermic (energy released):
Endothermic 
B2+C2-->2BC 
A2+C2-->2AC 
<span>A2+B2-->2AB</span>

Exothermic 
AB+C-->AC+B 
A+BC-->AB+C 

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Jupiter is denser than water, yet composed for the most part of two light gases, hydrogen and helium. What makes Jupiter as dens
Alex17521 [72]

it has a rocky core so the gravity from that compacts the gases extremly tight

7 0
3 years ago
A tiger travels 3m/s^2 for 4.1s,what was its initial speed if it's final speed was 55k/h?
zaharov [31]
Acceleration a=3m/s^2
time t= 4.1seconds
Final velocity V= 55km/h
initial velocity U= ?
First convert V to m/s
36km/h=10m/s
55km/h= 55*10/36=15.28m/s
Using the formula V= U+at
U= V-at
U= 15.28-3*4.1=15.28-12.3=2.98m/s
Initial velocity U= 2.98m/s or 10.73km/h (Using the conversion rate 36km/h=10m/s)
8 0
3 years ago
Sound is a type of mechanical wave and must have a medium through which to travel. Sound will move at different speeds when whic
Alex787 [66]
Hey there!

The answer would be B. The sound moves from air to water.

Sound travels through different mediums. It goes fastest in solids, a little slower in liquids, and slowest in air. Sound is a very fast wave, but remember that mediums can differ that. In a vacuum space, there is no sound at all. (ex. outer space)

Hope this helps !
5 0
3 years ago
The gage pressure in a liquid at a depth of 3 m is read to be 39 kPa. Determine the gage pressure in the same liquid at a depth
ioda

Answer: 117 kPa

Explanation:

For the liquid at depth 3 m, the gauge pressure is equal to = P₁=39 kPa

For the liquid at depth 9m, the gauge pressure is equal to= P₂

Now we are given the condition that the liquid is same. That must imply that the density must be same throughout the depth.

So, For finding gauge pressure we have formula P= ρ * g * h

Also gravity also remains same for both liquids

So taking ratio of their respective pressures we have

\frac{P_{1} }{\\P_2}= \frac{density * g * h_1}{density * g * h_2}

So \frac{39}{P_2}= \frac{3}{9}

Or P₂= 39 * 3 = 117 kPa

5 0
3 years ago
You might say that this experiment was an attempt to build a scale, and then calibrate it against a scale that we trust (the ele
Allushta [10]

No.

Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a random error has been minimized or even eliminated.

<h3>What is a random error?</h3>

Random error is defined as the deviation of the total error from its mean value due to chance.

Random errors can result from the instrument not being precise or from mistakes by the researcher.

Random errors can be minimized by taking multiple readings and averaging the results.

Since repeated measurements are taken and the average and 95% confidence interval are calculated, the possibility of the lack of agreement being a ransom error has been minimized.

Learn more about random errors at: brainly.com/question/22041172

3 0
3 years ago
Read 2 more answers
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