All categories

4 years ago

A star has a size of 0.1 solar radius. How many times larger is the sun than this star?

1 answer:

4 0

For this case, the first thing we are going to do is define variables:
x: size of the radius of the star
Y: size of the solar radio.
Let's write an equation that models the problem:
a star has a size of 0.1 solar radius:
 $x = 0.1y
$
 Clearing y we have:
 $y = x / 0.1
$
 Rewriting we have:
 $y = x / (1/10)

y = 10x$ 
Answer:
the sun is 10 times larger than this star

You might be interested in

If the flea jumps straight up, how high will it go? (Ignore air resistance for this problem; in reality, air resistance plays a

Savatey [412]

Answer:

The flea will reach to a height of 5.2 cm.

Explanation:

Let us assume it is given that, a flea reaches a takeoff speed of 1.0 m/s over a distance of 0.50 mm.

Initial speed, u = 1 m/s

Initial distance, x = 0.5 mm

We need to find the height reached by the flea. Using third equation of motion to find it.

At maximum height, its final speed, v = 0

$v^2-u^2=2ah$

Here, a = -g

$-u^2=-2g(h-x)\\\\1^2=2\times 9.8\times (h-0.5\times 10^{-3})\\\\h=0.052\ m$

h = 5.2 cm

So, the flea will reach to a height of 5.2 cm.

6 0

3 years ago

Speed in any given direction is called A. Trust B.velocity C.mass D.acceleration

ahrayia [7]

B. velocity is the speed in any given direction.

7 0

3 years ago

Read 2 more answers

A delivery truck leaves a warehouse and travels 2.60 km north. The truck makes a right turn and travels 1.33 km east before maki

charle [14.2K]

Answer:

$AD\approx1.7582\ km$

Explanation:

Follow the schematic in which point A is the warehouse and point D is the destination.

Now we observe the triangle constructed $\Delta ADB$ :

here:

$AB\perp BD$

$AB=2.6-1.45$

$AB=1.15\ km$

$BD=1.33\ km$

As we know that displacement is the shortest distance between two points.

Using Pythagoras theorem:

$AD=\sqrt{AB^2+BD^2}$

$AD=\sqrt{(1.15)^2+(1.33)^2}$

$AD\approx1.7582\ km$

3 0

3 years ago

Which of the following is an example of an object with kinetic energy?

Kaylis [27]

Answer:

A and C

Explanation:

Both have mass and are in motion

6 0

3 years ago

Read 2 more answers

A concave mirror produces a real image that is three times as large as the object. If the object is 20 cm in front of the mirror

TiliK225 [7]

Answer:

The image is produced 60 cm behind the mirror

The focal length of the mirror is 30 cm

Explanation:

u = Object distance = 20 cm

v = Image distance

f = Focal length

m = Magnification = 3

$m=-\frac{v}{u}\\\Rightarrow 3=-\frac{v}{20}\\\Rightarrow v=-3\times 20\\\Rightarrow v=-60\ cm$

The image is produced 60 cm behind the mirror

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{20}+\frac{1}{-60}\\\Rightarrow \frac{1}{f}=\frac{1}{30}\\\Rightarrow f=\frac{30}{1}=30\ cm$

The focal length of the mirror is 30 cm

8 0

3 years ago