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kramer
4 years ago
10

A portable electric heater has a resistance of 10 ohms. It plugs into a wall outlet that is 120 V. How much current, in amps, do

es it draw?
Physics
1 answer:
skad [1K]4 years ago
5 0

Answer:

12 A

Explanation:

I = V/R =  120 V/ 10 Ohm = 12 A

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What are the three equation of motion​
ycow [4]

Answer:

Three Equations of Motion are v = u + at; s = ut + (1/2) at² and v² = u² + 2as and these can be derived with the help of velocity time graphs using definition acceleration.

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<h3>Please Thanks to my 10 answer</h3>
3 0
3 years ago
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A boy im50kg at rest on a skateboard is pushed by another boy who exerts a force of 200 N on him. If the first boy's
sergey [27]

Answer:

Time, t = 2 seconds

Explanation:

Given the following data;

Mass, m = 50 kg

Initial velocity, u = 0 m/s (since it's starting from rest).

Final velocity, v = 8 m/s

Force, F = 200 N

To find the time, we would use the following formula;

F = \frac {m(v - u)}{t}

Making time, t the subject of formula, we have;

t = \frac {m(v - u)}{F}

Substituting into the formula, we have;

t = \frac {50(8 - 0)}{200}

t = \frac {50*(8)}{200}

t = \frac {400}{200}

Time, t = 2 seconds

5 0
3 years ago
Which of the following conducting wires has the least resistance?
ohaa [14]

Answer:

D

Explanation:

Copper wire at higher temperature

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3 years ago
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Found ones similar, but not with this question. Someone help?
agasfer [191]

The distance between the plates is 7.1 * 10^-7 m

<h3>What is the distance?</h3>

The capacitor is a device that is used to store charges. The capacitor always has a dielectric that is placed between the capacitors that separates them.

Given that;

C = εoA/d

C = capacitance

εo = permittivity of free space

A = cross sectional area

d = distance apart

Cd = εoA

d = εoA/C

d = 8.8 * 10^-12 * 8.89 * 10^-4/1.11 * 10^-8

d = 7.1 * 10^-7 m

Learn more about capacitor:brainly.com/question/17176550

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6 0
2 years ago
I really need help !!
Marat540 [252]

Answer:

The generator will work only if the magnetic field associated with the turns of coil change.

here both magnet and coil are stationary with respect to each other so no electromagnetic induction would take place. so no indiced current will be produced.

the student has to introduce some mechanism either to rotate the coil or the magnet

5 0
4 years ago
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