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labwork [276]
3 years ago
10

What property makes ocean water a good conductor of electricity

Physics
1 answer:
Lostsunrise [7]3 years ago
5 0

Answer:

The salt molecules (Sodium ions and Chlorine ions) in the ocean water makes it a good conductor of electricity.

Explanation:

Conductivity<em> refers to the ability of an object to transmit electricity.</em> Transmitting electricity means allowing electricity to pass through the material. The best conductor of electricity is <u>"silver."</u> Other elements which are also good conductors are: <em>gold, aluminum, copper, etc. </em>Those which are poor in conducting electricity are called insulators. These include <em>glass, plastic, rubber, paper, styrofoam, etc. </em>

<u>Ocean water is considered a good conductor of electricity because it contains Sodium ions and Chlorine ions.</u> Remember that ions carry electrical charges, which could either be positive or negative. <u>The Sodium ion here is positively charged, while the Chlorine ion is negatively charged.</u> Being mixed with water makes it an electrolyte solution. When electricity travels, it needs to have two sources: a positive terminal and a negative terminal. This means that the Sodium ions will be attracted to the electricity's negative terminal, while the Chlorine ions will be attracted to the positive terminal. This will allow the electrons to flow through the medium, thus creating a circuit for electricity to pass through.

This is the reason why ocean water is a good conductor of electricity.

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A music fan at a swimming pool is listening to a radio on a diving platform. The radio is playing a constant- frequency tone whe
joja [24]

Answer:

The Doppler Effect is given by the following relation;

f' = \left (\dfrac{v + v_0}{v - v_s} \right) \times f

Where;

f' = The frequency the observer hears

f = Actual frequency of the wave

v = The velocity of the sound wave

v_o = The velocity of the observer

v_s = The velocity of the source

Where the observer is stationary, we have;

(i) When the source is moving in the direction of the observer

f' = \left (\dfrac{v }{v - v_s} \right) \times f

(ii) When the source is receding from the observer, we have;

f' = \left (\dfrac{v }{v + v_s} \right) \times f

Therefore;

(a) A person left behind on the platform

For a person left behind on the platform, we have that the radio source is receding, therefore, we have;

f' = \left (\dfrac{v }{v + v_s} \right) \times f

(1) Given that (v + v_s) > v, therefore, v < (v + v_s), f' < f, the frequency heard by the person left on the platform, f', is smaller (lower) than the frequency produced by the radio

(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively smaller

(b) A person down below floating on a rubber raft

For the the person down below on the rubber raft, the radio source is advancing

Therefore, the radio source is moving towards the person at rest down on the rubber raft, therefore, we have;

f' = \left (\dfrac{v }{v - v_s} \right) \times f

(1) Given that (v - v_s) < v, therefore, f' > f, the frequency heard by the person down below floating on the rubber raft, f', is greater (higher) than the frequency produced by the radio

(2) The frequency is not constant as the speed of the source is increasing while it under the acceleration due to gravity

(3) During the fall, the speed of the source continuously increases under the effect of gravitational attraction and therefore the frequency heard by the person on the platform becomes progressively greater (higher)

Explanation:

7 0
3 years ago
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