Question

At a particular temperature, an equilibrium mixture the reaction below was found to contain 0.171 atm of I2, 0.166 atm of Cl2 and 9.81 atm of ICl. Calculate the value of the equilibrium constant, Kp at this temperature.I2(g) + Cl2(g) <=> 2 ICl(g)

Answer 1

Answer: 3390

Explanation:

Since this problem already gives is the equilibrium values, all we have to do is to plug them into the formula for $K_{p}$.

$K_{p} =\frac{[ICl]^2}{[I_{2}][Cl_{2}] }$

$K_{p} =\frac{(9.81)^2}{(0.171)(0.166)} =3390$