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Reil [10]
3 years ago
11

I have 0.92 moles of water (H20). What is the mass of the water?​

Chemistry
1 answer:
strojnjashka [21]3 years ago
5 0

Ans:

16.57 g

Explanation:

If you have 0.92 moles of water you would take your moles and multiply it by its molar mass (18.01528 g/mol) to find your specific mass.

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How many electrons, protons, neutrons, and what is the atomic number and atomic mass (if any) does Fluoride have?
ExtremeBDS [4]
Fluoride is an anion of Fluorine

What this means is that the two have the same number of protons (9), but Fluoride has 10 electrons compared to Fluorine's 9.

So the answers are:
Protons - 9
Neutrons - 9
Electrons - 10
Atomic Number - 9
Atomic Mass - 19 g/mol
5 0
3 years ago
Read 2 more answers
Compared to our solar system, the universe is
GuDViN [60]

Answer: Massive

Explanation: There are many galaxies out in the universe and it's possible they go on indefinitely. Out of all of these, our solar system is very very tiny. As an analogy, our universe would be like an atom which are the the smallest units of matter. There are many other galaxies that we just haven't been able to discover but they are there.

3 0
3 years ago
the development and use of the ______ a common and important piece of laboratory equipment, led scientist to the discovery of se
Liula [17]

The answer is the Microscope.

6 0
4 years ago
Calculate the pH and fraction of dissociation ( α ) for each of the acetic acid ( CH 3 COOH , p K a = 4.756 ) solutions. A 0.002
marysya [2.9K]

Answer:

The degree of dissociation of acetic acid is 0.08448.

The pH of the solution is 3.72.

Explanation:

The pK_a=4.756

The value of the dissociation constant = K_a

pK_a=-\log[K_a]

K_a=10^{-4.756}=1.754\times 10^{-5}

Initial concentration of the acetic acid = [HAc] =c = 0.00225

Degree of dissociation = α

HAc\rightleftharpoons H^++Ac^-

Initially

c

At equilibrium ;

(c-cα)                                cα        cα

The expression of dissociation constant is given as:

K_a=\frac{[H^+][Ac^-]}{[HAc]}

1.754\times 10^{-5}=\frac{c\times \alpha \times c\times \alpha}{(c-c\alpha)}

1.754\times 10^{-5}=\frac{c\alpha ^2}{(1-\alpha)}

1.754\times 10^{-5}=\frac{0.00225 \alpha ^2}{(1-\alpha)}

Solving for α:

α = 0.08448

The degree of dissociation of acetic acid is 0.08448.

[H^+]=c\alpha = 0.00225M\times 0.08448=0.0001901 M

The pH of the solution ;

pH=-\log[H^+]

=-\log[0.0001901 M]=3.72

3 0
3 years ago
A gamma ray photon has an energy of 4.75 x 10-14 joules. What is the frequency of this radiation?
Rama09 [41]

The frequency of the radiation is equal to 7.17  \times 10^{19} Hertz.

<u>Given the following data:</u>

  • Photon energy = 4.75 \times 10^{-14} Joules

To find the frequency of this radiation, we would use the Planck-Einstein equation.

Mathematically, the Planck-Einstein relation is given by the formula:

E = hf

<u>Where:</u>

  • h is Planck constant.
  • f is photon frequency.

Substituting the given parameters into the formula, we have;

4.75 \times 10^{-14} = 6.626 \times 10^{-34} \times F\\\\F = \frac{4.75 \times 10^{-14}}{6.626 \times 10^{-34}}

Frequency, F = 7.17  \times 10^{19} Hertz

Read more: brainly.com/question/16901506

4 0
3 years ago
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