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3 years ago

Which element would be a good conductor of heat and electricity?

Chemistry

2 answers:

eimsori [14]3 years ago

8 0

Your answer to your question is calcium

g100num [7]3 years ago

7 0

Answer:

Transitional metals are good conductors of both heat and electricity.

But since there aren't any. It could be Calcium.

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The distance from Santa Maria to Los Alamos is 16.25 mi. what is the distance in meters?

Radda [10]

Answer:

26,167.47m

Explanation:

Problem:

We are to solve this problem using dimensional analysis:

from the given conversion factors-

0.621mi = 1.00km

1km = 1000m

From the problem, we are groing from miles to metres:

16.25mi x $\frac{1km}{0.621mi}$ x $\frac{1000m}{1km}$

The mi will cancel out and also the km. This leaves us with the desired unit we want which is meters, m.

= 26,167.47m

7 0

3 years ago

The process of removing or adding electrons is called __________.

nikdorinn [45]

The process of removing or adding electrons is called ionization

5 0

3 years ago

Large-scale metamorphism is also know as _____ metamorphism. A. contact B. thermal C. regional D. nonfoliated

Fiesta28 [93]

Nonfoliated is the answer I belive.. Hopefully

7 0

3 years ago

Read 2 more answers

An analytical chemist is titrating of a solution of propionic acid with a solution of 224.9 ml of a 0.6100M solution of propioni

Svetllana [295]

Answer: The pH of acid solution is 4.58

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

For KOH:

Molarity of KOH solution = 1.1000 M

Volume of solution = 41.04 mL

Putting values in equation 1, we get:

$1.1000M=\frac{\text{Moles of KOH}\times 1000}{41.04}\\\\\text{Moles of KOH}=\frac{1.1000\times 41.04}{1000}=0.04514mol$

For propanoic acid:

Molarity of propanoic acid solution = 0.6100 M

Volume of solution = 224.9 mL

Putting values in equation 1, we get:

$0.6100M=\frac{\text{Moles of propanoic acid}\times 1000}{224.9}\\\\\text{Moles of propanoic acid}=\frac{0.6100\times 224.9}{1000}=0.1372mol$

The chemical reaction for propanoic acid and KOH follows the equation:

$C_2H_5COOH+KOH\rightarrow C_2H_5COOK+H_2O$

Initial: 0.1372 0.04514

Final: 0.09206 - 0.04514

Total volume of solution = [224.9 + 41.04] mL = 265.94 mL = 0.26594 L (Conversion factor: 1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[\text{salt}]}{[acid]})$

$pH=pK_a+\log(\frac{[C_2H_5COOK]}{[C_2H_5COOH]})$

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of propanoic acid = 4.89

$[C_2H_5COOK]=\frac{0.04514}{0.26594}$

$[C_2H_5COOH]=\frac{0.09206}{0.26594}$

pH = ?

Putting values in above equation, we get:

$pH=4.89+\log(\frac{(0.04514/0.26594)}{(0.09206/0.26594)})\\\\pH=4.58$

Hence, the pH of acid solution is 4.58

7 0

3 years ago

Which substance can be broken down by a chemical change

ELEN [110]

Lots of substances. Rocks, metals, minerals, you name it.

5 0

2 years ago

Read 2 more answers