The oxidation state of a substance is the electric charge it is exhibiting in a given state. This may be determined by looking at the oxidation states of accompanying atoms as well as the charge on the complete molecule.
In this case:
Molecular charge: 0
Oxidation state of oxygen: -2 (it is a group 6 element)
Thus,
S + 3 * -2 = 0
S = 6
Sulfur is exhibiting an oxidation state of +6.
It is important to establish the true weight of the crucible because it is a necessary reference point. Later, you will be weighing the crucible to determine how much of the products are present, so it's necessary to have the true tare weight of the crucible.
<span>The crucible is heated to be sure it is free of any moisture or other volatiles that might otherwise give a misleading weight. If you start out with the crucible absolutely clean and dry, (after heating) then you know that any additional weight must have come from the sample.</span>
The pressure of the gas would be the dividend divided by the number of the second vi~2
He is using the filtration method.
It’s a technique which is used for separation of solids and fluids by putting them through a medium which allows only fluid to pass through, leaving the solids (in this case the soil) alone.
The fluid that passed is called the filtrate.
Answer:
1500ml
Explanation:
molarity=3.65⋅g36.5⋅g⋅mol−1500⋅mL×10−3⋅L⋅mL−1=0.200⋅mol⋅L−1